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Alexxx [7]
4 years ago
14

4. Is it possible for two different compounds to be made from the exact same two elements? Why or why not? With a limited number

of elements (less than 120 are known), does this mean we also have a small number of compounds or do we have a large number of compounds in this world?
Chemistry
1 answer:
densk [106]4 years ago
3 0

no it is not possible, because they both have the same number of valence electrons in each element. in a compound you are supposed to have two or more elements that have different numbers of valence electrons so when put together they for a compound.

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Be sure to use proper significant figures. The molecular weight of NaCl is 58.44 grams/mole. To prepare a 0.50 M solution: You w
Misha Larkins [42]
Your answer would be,
Molarity = moles of solute/volume of solution we needed, 29.22(g)(mol) of NaCI

= 29.22(g)/58.44(g)(mol^-1)(1)/1(L)
= 0.500(mol)(L^-1)



Hope that helps!!!
5 0
3 years ago
Read 2 more answers
You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el
Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.  

For example;  

  Given a number 5;  

     We know the number is made of both the atomic number of the element and the highest quantum number.  

  It is easier for us to know the highest quantum number from the shell notation:  

        shell notation 1s²2s²2p¹

        highest principal quantum number is 2

  We are left with atomic number 5-2, which is 3

           The element is therefore Li.  

Part A.   5,     30,      58,      56,     99,     79,    19,     98,     9

             Li       Fe        I         Sb       U       Ta      S      Pa     N

Part B.   9,    99,    30,     95,     19,     47,     79

             N      U       Fe      Ra      S       Mo     Ta

Learn more:  

s-orbital brainly.com/question/9288609

#learnwithBrainly

4 0
3 years ago
Cellulose and starch are examples of:
mixer [17]

Answer:

The choose (d)

d. polysaccharides

3 0
3 years ago
Read 2 more answers
Iron 3 oxide and carbon react to form iron and carbon dioxide. Balance the equation.
Oksi-84 [34.3K]

Answer:

2 Fe(iii)2O3 + 3 C ==> 2 Fe  + 3 CO2

Explanation:

First of all, you have to translate the words into an equation.

Fe(iii)2O3 + C ==> Fe  + CO2

The easiest way to tackle this is to start with the Oxygens and balance them. They must balance by going to the greatest common factor which is 6. So you multiply the molecule by whatever it takes to get the Oxygens to 6

2 Fe(iii)2O3 + C   ==>     Fe  + 3 CO2

Now work on the irons. There 2 on the left and just 1 on the right. So you need to multiply the iron by 2.

2 Fe(iii)2O3 + C ==> 2 Fe  + 3 CO2

Finally it is the turn of the carbons. There are 3 on the right, so you must make the carbon on the left = 3

2 Fe(iii)2O3 + 3 C ==> 2 Fe  + 3 CO2

And you are done.

5 0
3 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
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