Y is such that 4y _ 7<= 3y and 3y <= 5y +8. What range of values of y satisfies both inequalities
1 answer:
Answer:
<h3>-4≤y≤7</h3>
Step-by-step explanation:
Given the inequality expressions
4y - 7 ≤ 3y and 3y≤5y+8
For 4y - 7 ≤ 3y
Collect like terms
4y - 3y ≤ 7
y ≤ 7
For 3y≤5y+8
Collect like terms
3y - 5y ≤ 8
-2y ≤ 8
y ≥ 8/-2
y ≥ -4
Combining both solutions
-4≤y≤7
<em>Hence the range of values of y that satisfies both inequalities is -4≤y≤7 </em>
You might be interested in
Answer: Store 2
Step-by-step explanation: sorry I don’t know how to explain.
Answer:
10
Step-by-step explanation:
5*2=10
10*1=10
so 1/5=2/10
Answer:
should be 1350cm^2
Step-by-step explanation:
hope this helps
Add it tighter and it will make ur number then subtract that
50% is equal to 5/10 so 5/10 were party cakes 1/5x2=2/10 so 2/10 were fruit cakes 5/10+2/10=7/10 so 10/10 which is 100% of all cakes 10/10-7/10=3/10 so 3/10 of the cakes were sponge cakes.
