Y is such that 4y _ 7<= 3y and 3y <= 5y +8. What range of values of y satisfies both inequalities
1 answer:
Answer:
<h3>-4≤y≤7</h3>
Step-by-step explanation:
Given the inequality expressions
4y - 7 ≤ 3y and 3y≤5y+8
For 4y - 7 ≤ 3y
Collect like terms
4y - 3y ≤ 7
y ≤ 7
For 3y≤5y+8
Collect like terms
3y - 5y ≤ 8
-2y ≤ 8
y ≥ 8/-2
y ≥ -4
Combining both solutions
-4≤y≤7
<em>Hence the range of values of y that satisfies both inequalities is -4≤y≤7</em>
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Answer:
b=2A/h-a
Step-by-step explanation:
A=1/2h(a+b)
a+b=A/(1/2h)
a+b=A/(h/2)
a+b=(A/1)(2/h)
a+b=2A/h
b=2A/h-a
Answer:
m = -2/1 or just m = -2
Step-by-step explanation:
Answer:
x=13
Step-by-step explanation:
13-6=7
Then the 9
2(13)-19=7
7+7=14
14+9=23
After rounding off, Answer is 6.
Hope this helps. - M
The origin. Hope this helps.