Answer:
balanced equation mole ratio 5 2 mol NO/1 mol O2
10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2
20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO
actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2
Because the actual mole ratio of NO:O2 is larger than the balanced equation mole
ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.
Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO
0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO
Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2
Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N
Explanation:
Answer:
C)
Explanation:
The warmer the molecules, the higher the average kinetic energy.
"As stated in the kinetic-molecular theory, the temperature of a substance is related to the average kinetic energy of the particles of that substance. When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles. This is registered as an increase in the temperature of the substance." -lumen learning
(I know for sure but what think... hope this helped)
The classification of living things makes it easier for scientists to answer many important questions.
Examples:
-How many known species are there?
-What are the defining characteristics of each species?
-What are the relationships between these species?
1 mole of any particles = 6.02* 10²³ particles
4.5*10²⁵ atoms Ni* 1 mol Ni/6.02*10²³ Ni ≈ 74.75≈ 75 mol Ni
The number of atoms of oxygen is 2.4 * 10^24.
<h3>How many atoms are produced?</h3>
We know that mole of a substance contains the Avogadro's number of atoms. The Avogadro's number gives the number of atoms, molecules, ions and atoms that could be found in one mole of a substance.
Now;
Given that ;
1 mole of oxygen contains two atoms of oxygen, the number of atoms that are contained in 2 moles of the oxygen molecule is;
2 * 2 * 6.023 * 10^23
= 2.4 * 10^24
Learn more about dimensional analysis:brainly.com/question/13078117
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