Answer:
4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ
Explanation:
2N2H4(2) + N204 (1) --> 3N2 (g) + 4H20 (g),AHO-1049 kJ
when 6 mol of nitrogen are formed?
The ratio of Nitrogen in the previous therrmochemical equation to when 6 mol f nitrogen are formed is 2; 6/3 = 2.
So to get the new thermoochemical equation, multiply all parameters in the given equation by 2.
We have;
4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ
Answer:
0.47 M
Explanation:
The concentration of the solution can be calculated using the following equation:

<u>Where:</u>
V: is the volume of the solution = 68.6x10⁻² L
η: is the moles of cobalt (II) sulfate
m: is the mass of cobalt (II) sulfate = 89.94 g
M: is the molar mass of cobalt (II) sulfate = 281.103 g/mol
The concentration of cobalt (II) sulfate is:
We used the molar mass of the cobalt (II) sulfate heptahydrate (281.103 g/mol) since it is one of the most common salts of cobalt.
Therefore, the concentration of a solution of cobalt (II) sulfate is 0.47 M (assuming that the cobalt (II) sulfate is heptahydrate).
I hope it helps you!
Atoms are never rearranged
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