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Stella [2.4K]
3 years ago
11

a rock dropped in a graduated cylinder raises the level of water from 20 ml to 35 ml. the rock has mass of 45 g. what is the den

sity of the rock.
Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

15...

Explanation:

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What effect does filtration have on water with a ph of 3?
creativ13 [48]

Answer:

None  

Step-by-step explanation:

A high pH is caused by an excess of hydrogen ions over hydroxide ions.

Hydrogen ions are so small that they pass through the pores of an ordinary filter.

Thus, ordinary filtration has no effect on the pH of water.

4 0
3 years ago
How many molecules are there in 2.3g Of carbon
Alexxandr [17]

Answer: 1.15x10²³ molecules C

Explanation: solution attached:

Convert mass of C to moles using its molar mass then multiply to the Avogadro's number.

8 0
3 years ago
Read 2 more answers
A student titrates a 10.00mL sample of an HCl solution, using 0.359 M solution of NaOH. She finds that 24.75mL of sodium hydroxi
salantis [7]
HCl and NaOH react in a 1:1 ratio, meaning that 1 H+ from HCl will react with 1 OH- from NaOH. Knowing this, and that molarity is mol/liter, all we need to do is use what we have available. First we must find the mols of HCl in our solution, so we set up the following equation in the following steps:
1. 24.75mL x (0.359mol NaOH / 1000mL) = 8.885 x 10^-3mol NaOH
   This is done in order to find the mols of NaOH to convert to mols of HCl.
2. 8.885x10^-3mol NaOH x (1 mol HCl/1mol NaOH) = 8.885 x 10^-3mol HCl
   Here we just used the mols of NaOH we found to convert to mols of HCl using the 1:1 ratio described earlier.

From the mols of HCl all we have to do is divide by the amount of liters in the solution. Since we started with 10mL HCl and added 24.75mL NaOH, the total volume is 34.75mL = 0.03475L. So:
8.885 x 10^-3mol HCl/0.03475L = 2.557 x 10^-1M HCl
However, this is the molarity of the HCl and NaOH solution, not the original HCl solution. Using the dilution equation M1V1=M2V2, we can solve for the original molarity.
M1 = the molarity of our HCl in the titrated mixture (2.557 x 10^-1M HCl)
V1 = the total volume that our mixture has (34.75mL = 0.03475L)
M2 = what we're trying to find
V2 = the amount of the original HCl that we had (10mL = 0.010L)
Simply solving for M2 gives us:
M2 = (M1V1) / V2 or:
M2=((2.557 x 10^-1) x 0.03475L) / 0.010L = 8.89 x 10^-1M HCl. That is your answer.
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3 years ago
Help please asap will mark brainliest!! My time is running out.
sukhopar [10]

Answer:

I dont know sorry.

Explanation:

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Answer:

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