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Stella [2.4K]
3 years ago
11

a rock dropped in a graduated cylinder raises the level of water from 20 ml to 35 ml. the rock has mass of 45 g. what is the den

sity of the rock.
Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

15...

Explanation:

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What is the oxidation number of Gallium?
love history [14]

Answer:

+3

Explanation:

Sorry, I don't have one for now. I remember answering this a while ago, but I don't remember the exact reason why it's 3+.

5 0
4 years ago
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When balancing a chemical equation, the number of h atoms in 2 ch4 is eight?
Viktor [21]
Yes... that is correct.

CH4 is methane so the coefficent in front of it would double the number of atoms of each element
6 0
3 years ago
Hydrogen gas is collected over water at 21 degrees Celsius. At 21 degrees Celsius the vapor pressure of water is 18.7 torr. If t
Alinara [238K]

Answer : The pressure of hydrogen gas is, 739.3 torr

Explanation :

As we are given:

Vapor pressure of water = 18.7 torr

Barometric pressure = 758 torr

Now we have to calculate the pressure of hydrogen gas.

Pressure of hydrogen gas = Barometric pressure - Vapor pressure of water

Pressure of hydrogen gas = 758 torr - 18.7 torr

Pressure of hydrogen gas = 739.3 torr

Therefore, the pressure of hydrogen gas is, 739.3 torr

3 0
3 years ago
How does one recognize a redox reaction?
nika2105 [10]

Answer:

A.

Explanation:

A redox reaction is a reaction when oxidation states (or numbers) change during reaction.

3 0
3 years ago
The gauge pressure inside a vessel is ‐40kPa, at an elevation of 5000m. a) What is the absolute pressure? b) At this elevation,
hoa [83]

Answer:

a) Pabs = 48960 KPa

b) T = 433.332 °C

Explanation:

  • Pabs = Pgauge + d*g* h

∴ d = 1000 Kg/m³

∴ g = 9.8 m/s²

∴ h = 5000 m

∴ P gauge = - 40 KPa * ( 1000 Pa / KPa ) = - 40000 Pa; Pa≡Kg/m*s²

⇒ Pabs = - 40000 Kg/ms² + ( 1000 Kg/m³ * 9.8 m/s² * 5000 m )

⇒ Pabs = 48960000 Pa = 48960 KPa

a) at that height and pressure, we find the temperature at which the water boils by means of an almost-exponential graph which has the following equation:

P(T) = 0.61094 exp ( 17.625*T / ( T + 243.04 ))......P (KPa) ∧ T (°C)....from literature

∴ P = 48960 KPa

⇒ ( 48960 KPa / 0.61094 ) = exp ( 17.625T / (T+ 243.04))

⇒ 80138.803 = exp ( 17.625T / ( T + 243.04))

⇒ Ln ( 80138.803) = 17.625T / ( T + 243.04))

⇒ 11.292 * ( T + 243.04 ) = 17.625T

⇒ 11.292T + 2744.289 = 17.625T

⇒ 2744.289 = 17.625T - 11.292T

⇒ 2744.289 = 6.333T

⇒ T = 433.332 °C

3 0
3 years ago
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