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2 years ago

As the concentration of a KOH solution increases, the number of moles of HCl needed to neutralize the KOH solution?

Chemistry

1 answer:

Soloha48 [4]2 years ago

8 0

B) increasesAnswer:

Explanation:

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An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams

tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0

3 years ago

"What quantitative measurement and qualitative observations can be made about the interactions of matter and energy?" can someon

kirza4 [7]

Quantitative measurements are numerical values, they involve amounts and units like measuring things. Qualitative observations appeal to the five senses, like what does the interaction look and sound like

5 0

3 years ago

Which of these is most likely to form between elements transferring electrons to

Stella [2.4K]

Answer: The answer is an ionic bond

6 0

3 years ago

Read 2 more answers

Consider this question: What is the molarity of HCL if 35.23 mL of a solution of HCL contains 0.3366 g of HCL?

Crazy boy [7]

<u>Answer:</u> The molarity of HCl solution is 0.262 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of HCl = 0.3366 g

Molar mass of HCl = 36.5 g/mol

Volume of the solution = 35.23 mL

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.3366g\times 1000}{36.5g/mol\times 35.23mL}\\\\\text{Molarity of HCl}=0.262M$

Hence, the molarity of HCl solution is 0.262 M.

6 0

3 years ago

If you have 85g of sulfur dioxide at STP, how many moles do you have?

Step2247 [10]

Answer: 1.32

Explanation:

Given

85 gm of sulfur dioxide is present at STP

The molar mass of sulfur dioxide is $32+2\times 16=64\ g/mol$

The number of moles of sulfur dioxide is

$\Rightarrow n=\dfrac{85}{64}\\\\\Rightarrow n=1.32\ \text{mol}$

3 0

3 years ago