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katovenus [111]

2 years ago

8

As the concentration of a KOH solution increases, the number of moles of HCl needed to neutralize the KOH solution?

1 answer:

Soloha48 [4]2 years ago

8 0

B) increasesAnswer:

Explanation:

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How much pressure does an elephant with a mass of 2200 Kg and a total footprint area of 4500 cm2 exert on the ground?

Debora [2.8K]

Answer:

47911.1 pa

Explanation:

The SI base unit of pressure is pascal, which is N/m^2.

2200 kg is 2200*9.8=21560 N, and 4500 cm^2=4500/10000=0.45 m^2.

So the total pressure exerted on the ground (!!) is 21560/0.45= 47911.1 Pa.

6 0

3 years ago

Read 2 more answers

The number of molecules in 1.0 mole of H2O is the same as in one mole of O2.

zaharov [31]

True. A mole of anything has the same amount of molecules. 1 mole = 6.022 x 1023 molecules

8 0

3 years ago

Read 2 more answers

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

3 years ago

Suppose that CO2 in the atmosphere was held at a constant, natural level for a few thousand years. Then, CO2 was added to double

MissTica

Answer:

temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Explanation:

CO2 in the atmosphere has the property of trapping heat by absorbing it. So, with increase in the level of CO2 in the atmosphere the more heat will be absorbed by it and hence the temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Level of CO2 ∝ Temperature of the Earth

8 0

3 years ago

What is the concentration of a solution if 0.450 mol of NaCl dissolved in 750 mL of water?

Thepotemich [5.8K]

Answer:

.6mol/L

Explanation:

molarity = number of moles / volume of solvent (in L)

750mL / 1000mL/L = .75L

M = .450mol / .75L

M = .6mol/L

3 0

3 years ago