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katovenus [111]
3 years ago
8

As the concentration of a KOH solution increases, the number of moles of HCl needed to neutralize the KOH solution?

Chemistry
1 answer:
Soloha48 [4]3 years ago
8 0

B) increasesAnswer:

Explanation:

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andrey2020 [161]

<u>Answer: </u>

The value of \left(2.5 \times 10^{10}\right) \times\left(3.5 \times 10^{-7}\right) is 8750

<u>Solution: </u>

\left(2.5 \times 10^{10}\right) \times\left(3.5 \times 10^{-7}\right)

\Rightarrow\left(2.5 \times 10^{10} \times 3.5 \times 10^{-7}\right)

\Rightarrow\left(2.5 \times 3.5 \times\left(10^{10} \times 10^{-7}\right)\right)

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