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pochemuha
3 years ago
7

How many moles is 90.93 grams of aluminum?

Chemistry
1 answer:
Rashid [163]3 years ago
6 0

Answer:

C) 3.37 moles .

Explanation:

Hello,

In this case, considering that the atomic mass of aluminum is 27.0 g/mol, the moles in 90.93 g of aluminum are computed via the following dimensional analysis:

n=90.93 gAl*\frac{1molAl}{27.0gAl} \\\\n=3.37molAl

Thus, answer is C) 3.37 moles .

Best regards.

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6.0 moles of Na and 4.0 moles of Cl2 are mixed, how manu moles of NaCl in moles cane be made from this mixture
Sladkaya [172]

Answer:

Moles of NaCl formed is 6.0 moles

Explanation:

We are given the equation;

2 Na(s) + Cl₂(g) → 2 NaCl(s)

  • Moles of Na is 6.0 moles
  • Moles of Cl₂ is 4.0 moles

From the reaction;

2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl

In this case;

6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.

Thus, the rate limiting reagent is sodium.

But, 2 moles of sodium reacts to form 2 moles of NaCl

Therefore;

Moles of NaCl = Moles of Na

                      = 6.0 moles

Thus, moles of sodium chloride produced is 6.0 moles

3 0
3 years ago
0. A liquid solution of LiCl in water at 25°C contains 1 mol of LiCl and 7 mol of water. If 1 mol of LiCl⋅3H2O(s) is dissolved i
kupik [55]

Answer:

19.488 kJ

Explanation:

The overall reaction mechanism shows the reaction between LiCl and H₂O

LiCl.3H_2O ------> Li +\frac{1}{2} Cl_2+3H_2+\frac{3}{2} O_2     -------- (1)

2Li+Cl_2+10H_2O ----->LiCl.10H_2O              -------- (2)

3H_2+\frac{3}{2}O_2 -----> 3H_2O                                     --------- (3)

LiCl.7H_2O ------>  Li + \frac{1}{2} Cl_2+7H_20             ---------- (4)

The overall reaction =

LiCl.7H_2O +LiCl.3H_2O ------>  2LiCl.10H_2O

The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively

The overall enthalpy change is:

\delta H = \delta H _{LiCl.3H_2O}+\delta H_{3H_2O}  + \delta  H_{2(LiCl.5H_2O)} + \delta  H _{liCl.7H_2O}

\delta H =Q at constant pressure;

Thus; Q = 1311.3 (kJ)  857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)

Q = 19.488 kJ

Thus, the heat effect = 19.488 kJ after the addition of  1 mol of LiCl⋅3H2O(s)

4 0
3 years ago
How many atoms of each element are in 4Na3PO4?
velikii [3]

Answer:

12 sodium 4 phosphorus 16 oxygen.  makes the table below to determine the number of atoms of each element in the chemical formula 4Ca(ClO3)2.

8 0
3 years ago
Read 2 more answers
Based on the chemical equation, use the drop down menu to choose the coefficients that will balance the chemical equation:
GREYUIT [131]

The answers would be 3 and 2 so the subscripts would both equal 6.

5 0
3 years ago
Read 2 more answers
How many grams of K2O will be produced from 0.50 g of K<br> and 0.10 g of O2?
Rudik [331]

Answer:

0.6g

Explanation:

Given parameters:

Mass of K = 0.5g

Mass of O₂  = 0.10g

Unknown:

Mass of K₂O  = ?

Solution:

To solve this problem, let us write the reaction equation first;

                   4K   +   O₂     →     2K₂O

The reaction above delineates the balanced chemical reaction.

To solve this problem, we need to know the limiting reactant. This reactant is the one that determines the amount and extent of the reaction because it is given in short supply. The other reactant is the one in excess.

Start off by find the number of moles of the reactant;

     Number of moles =  \frac{mass}{molar mass}

         Molar mas of K  = 39g/mol

          Molar mass of O₂   = 2(16) = 32g/mol

 Number of moles of K  = \frac{0.5}{39}   = 0.013moles

 Number of moles of O₂    = \frac{0.1}{32}   = 0.031moles

From the balanced reaction;

          4 moles of K reacted with 1 mole of O₂

         0.013 moles of K will react with \frac{0.013}{4}   = 0.0078 moles of O₂

We see that oxygen gas is in excess. We were given 0.031moles of the gas but only require 0.0078moles of oxygen gas.

The limiting reactant is potassium.

    therefore;

              4 moles of K produced 2 moles of K₂O

             0.013 moles of K will produce \frac{0.013 x 2}{4}   = 0.0065‬moles of K₂O

to find the mass of K₂O;

   Mass of K₂O  = number of moles x molar mass

                Molar mass of K₂O  = 2(39) + 16  = 94g/mol

  Mass of K₂O = 0.0065 x 94  = 0.6g

7 0
3 years ago
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