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fgiga [73]
2 years ago
7

Pls answer quick will mark brainlest and 5 stars

Physics
2 answers:
QveST [7]2 years ago
7 0

Answer:A

Explanation:

It’s bigger I am not sure

11111nata11111 [884]2 years ago
6 0

Answer:

For the first question, the answer is

B. Kettle

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5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
kari74 [83]

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

8 0
3 years ago
A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun
murzikaleks [220]
As long as all the waves stay in the same medium, the intensity of
any waves ... electromagnetic or mechanical ... decrease in proportion
to the square of the distance.

If the distance increases to 3 x the original distance, then the intensity
changes to  1/3² or 1/9 of the original intensity.

I suppose choice-'d' is the correct one, but I have to tell you that
the phrase "nine times as low" is mathematically meaningless,
and it really grinds my gears.
5 0
3 years ago
Read 2 more answers
John has decided he needs to work harder on his Social Studies project. Then, his teacher says if he gets a good grade in Social
bezimeni [28]

Answer: Extrinsic to intrinsic

Explanation:

8 0
3 years ago
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The gun, mount, and train car of a railway had a total mass of 1.22 x 10^6 kg. The gun fired a projectile that was 80 cm in diam
kakasveta [241]
1) According to the law of conservation of momentum .. 
<span>Horiz recoil mom of gun (M x v) = horiz. mon acquired by shell (m x Vh) </span>

<span>1.22^6kg x 5.0 m/s = 7502kg x Vh </span>
<span>Vh = 1.22^6 x 5 / 7502 .. .. Vh = 813 m/s </span>

<span>Barrel velocity V .. .. cos20 = Vh / V .. ..V = 813 /cos20 .. .. ►V = 865 m/s </span>

<span>2) Using the standard range equation .. R = u² sin2θ /g </span>

<span>R = 865² x sin40 / 9.80 .. .. ►R = 49077 m .. (49 km)</span>
5 0
3 years ago
Sir Dudley the Dextrous is loading cannons on top of the castle's tallest towers in preparation for an expected attack. He slips
JulsSmile [24]

Answer:

6667.9 J

Explanation:

We are given that

Mass of cannon.m=14 kg

Time,t=3.15 s

Initial velocity,u=0

We have to find the work done by gravity on the falling cannon ball.

g=9.8 m/s^2

h=ut+\frac{1}{2}gt^2

Substitute the values

h=0+\frac{1}{2}\times 9.8\times (3.15)^2=48.6 m

Work done,W=mgh

Using the formula

W=14\times 9.8\times 48.6=6667.9 J

4 0
3 years ago
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