Answer:
B
Explanation:
Heat moves as thermal energy from hot body to a cold body
don't forget to rate answer
Explanation:
Formula to calculate specific rotation is as follows.
Specific rotation (
) = 
where,
= observed rotation
c = concentration in g/ml
l = path length in dm
It is given that,
c =
= 0.02 g/ml
l = 20 cm = 2 dm (as 1 dm = 10 cm)
Therefore, calculate the specific rotation as follows.
Specific rotation (
) = 
= 
=
Thus, we can conclude that the specific rotation of this compound is
.
In a way, all of the answers could be argued for (for example: in the first option: if the scientists' opinions are understood to be "informed understanding of the causes of events"), but one of the options is the best:
Scientific laws describe specific relationships in nature without offering
an explanation.
The reason why I think this is true is that many laws are phased too short and too concise to provide comprehensive explanations, instead they describe the relationships that must hold.
One of the options is pplain false:
Scientific laws explain why natural events occur. -"Scientific laws were theories that have been tested, proven, and adopted as laws." - since they are not adopted as laws.
1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
Learn more about number of atoms at: brainly.com/question/8834373
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Answer:
See explanation.
Explanation:
Hello!
In this case, we can proceed as follows:
1. Here, the undergoing chemical reaction is:

Thus, the moles and mass of water turn out:

2. Here, the undergoing chemical reaction is:

So the required moles of HCl and the yielded of water are:

3. Here, the undergoing chemical reaction is:

Now, we apply each mole ratio obtain:
A.

B.

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