What is the area called in which the electrons are found ?

Moderate alcohol consumption is no more than ________ alcoholic drink(s) daily for adult women and up to ________ drink(s) daily

liberstina [14]

Moderate alcohol consumption is no more than $One$ alcoholic drink(s) daily for adult women and up to $Two$ drink(s) daily for adult men.

What is an alcohol?

Alcohol is an organic compound containing a hydroxyl group and a carbon atom; Alcohol can be an intoxicant found in alcoholic beverages.

An alcoholic drink (also called an alcoholic beverage, adult beverage, or simply a drink) is a drink that contains ethanol, a type of alcohol that acts as a drug and is produced by fermentation of grains, fruits, or other sources of sugar.

The consumption of alcoholic drinks, often referred to as "drinking", plays an important social role in many cultures. Most countries have laws regulating the production, sale, and consumption of alcoholic beverages.

So, according to the scientific studies, the alcoholic consumption for women in a day is not more then one and for men is not for two drink(s)

1 Drink includes:

For beer: 355 ML

For Wine: 148 ML

Learn more about alcohol: brainly.com/question/22875792

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6 0

2 years ago

What is the weight in grams of 3.36 × 10Æ³ molecules of copper sulfate (CuSOÁ)?

spin [16.1K]

Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g

hope this helps!

6 0

3 years ago

In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account

hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.