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Svet_ta [14]
2 years ago
5

What is speed? If you walk 3 kilometers in 30 minutes, what is your average speed in kilometers per hour? Compare and contrast i

nstantaneous and average speed. What distance will a truck travel in 3 hours at an average speed of 50 miles per hour?
Chemistry
1 answer:
Mrrafil [7]2 years ago
3 0

Answer:

See explanation

Explanation:

distance = 3 kilometres

time = 30 minutes or 0.5 hours

speed = distance/time = 3/0.5 = 6 Kmhr-1

Average speed is given by total distance covered divided by the total time taken while the instantaneous speed is the speed of an object at a particular instant or moment in time. Average speed refers to the whole journey while instantaneous speed refers to a particular point or instant in the journey.

distance= x

time = 3 hours

speed = 50 miles per hour

speed = distance/time

distance = speed * time

distance = 3 * 50

distance = 150 miles

You might be interested in
How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci
horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ +  2HCl  →  CaCl₂  + CO₂  +  H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0
3 years ago
NEED HELP ASAPPP<br><br> What is the number of beryllium atoms in 78.0g of Be?
polet [3.4K]

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

4 0
3 years ago
Given the following reaction:
Wewaii [24]

Answer:

Approx. 4⋅g.

Explanation:

Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.

Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.

Given the stoichiometry,

mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.

Why did I multiply the mass in this equation by 2? Am I pulling your leg?

3 0
2 years ago
Number 39! Please explain step by step!!!
ahrayia [7]

Answer:

The answer to your question is The honda civic hybrid weights 13181.8 N or 1318.2 kg

Explanation:

Data

Weight = 2900 lb

Weight = ? N

mass = ? kg

1 kg ------- 10 N

0.22lb ---- 1N

Use proportions to solve this problem

                        0.22 lb ------------------- 1 N

                        2900 lb -----------------  x

                         x = (2900 x 1) / 0.22

                         x = 2900 / 0.22

                        x = 13181.8 N

                          1 kg ----------------------- 10 N

                           x     ----------------------- 13181.8 N

                           x = (13181.8 x 1)/10

                           x = 1318.2 kg

                       

7 0
3 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
2 years ago
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