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Alenkasestr [34]
2 years ago
7

Which change will cause more CO2 to form in a closed container?​

Chemistry
1 answer:
EastWind [94]2 years ago
8 0

Answer:

Option C Removing Na₂CO₃

Option E Heating the container.

Explanation:

The equation for the reaction is given below:

2NaHCO₃ (s) <=> Na₂CO₃ (s) + CO₂ (g) + H₂O (g)

Enthalpy change (ΔH) = 136 KJ

To obtain more CO₂ do the following:

1. Add more NaHCO₃

From chemical equilibrium, adding more NaHCO₃ means the reactant has increase. Thus, it (the reactant) will react to form more product (CO₂)

2. Removing any of the products. Removing any of the products implies that more reactants are in the reaction vessel than the product. Thus, the reactants will react to produce more products (CO₂)

3. Heating the container. Heating the container will lead to an increase in the temperature of the reaction. Since the enthalpy change (ΔH) is positive it means the reaction is endothermic. Thus, heating the container i.e increasing the temperature will favours the forward reaction i.e more products will be obtained.

NOTE: Pressure has no effect in the reaction system since there is no gaseous reactants.

Considering the options given above, C and E gives the correct answer to the question.

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Most molecules that contain carbon are _____?
hjlf
<span>Most molecules containing carbon are organic. All organic compounds, from basic elements through complex living creatures, contain some degree of carbon, which is one of the most basic components of any organic molecule.</span>
7 0
3 years ago
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If the density of pure water is 0.9922 g/mL at 40 ºC, calculate its theoretical molarity at that temperature. Report to 4 sig fi
OleMash [197]
Answer is: theoretical molarity of water is 55.1222 mol/L.<span>
d(H</span>₂O) = 0.9922 g/mL.
M(H₂O) = 2 · Ar(H) + Ar(O) · g/mol.
M(H₂O) = 2 + 16 · g/mol = 18 g/mol.
c(H₂O) = d(H₂O) ÷ M(H₂O).
c(H₂O) = 0.9922 g/mL ÷ 18 g/mol.
c(H₂O) = 0.0551 mol/mL.
c(H₂O) = 0.0551 mol/mL · 1000 mL/L = 55.1222 mol/L.
3 0
3 years ago
While finding the number of molecules of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be
zvonat [6]

Answer

Avogadro's number: One mole of any substance contains 6.022×10²³ molecules

Explanation

While finding the number of moles of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be Avodagro's number, which is

One mole of any substance contains 6.022×10²³ molecules.

8 0
1 year ago
Explain what it means to be considered a “renewable” energy source, and what it means to be a “non-renewable” energy source.
Neporo4naja [7]

Answer: Resources are characterized as renewable or nonrenewable

- a renewable resource can replenish itself at the rate it is used such as solar energy, wind energy, hydro energy, and tidal energy.

- a nonrenewable resource has a limited supply such as coal, gas, nuclear energy, and fossil fuels.

3 0
2 years ago
Calculate the % composition of the unknown liquid using your most precise result. It is a mixture of ethanol (D[ETOH] = 0.7890 g
Rufina [12.5K]

% composition of ethanol = 34.51%

% composition of water  = 65.49%

<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

0.926 = \frac{x X  0.7890 g/mL  \;+  (100-x) X  0.9982 g/mL}{100}

x= 34.51 %

Hence,

% composition of ethanol = 34.51%

% composition of water = 65.49%

Learn more about the density here:

brainly.com/question/952755

#SPJ1

8 0
2 years ago
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