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3 years ago

Which change will cause more CO2 to form in a closed container?

Chemistry

1 answer:

EastWind [94]3 years ago

8 0

Answer:

Option C Removing Na₂CO₃

Option E Heating the container.

Explanation:

The equation for the reaction is given below:

2NaHCO₃ (s) <=> Na₂CO₃ (s) + CO₂ (g) + H₂O (g)

Enthalpy change (ΔH) = 136 KJ

To obtain more CO₂ do the following:

1. Add more NaHCO₃

From chemical equilibrium, adding more NaHCO₃ means the reactant has increase. Thus, it (the reactant) will react to form more product (CO₂)

2. Removing any of the products. Removing any of the products implies that more reactants are in the reaction vessel than the product. Thus, the reactants will react to produce more products (CO₂)

3. Heating the container. Heating the container will lead to an increase in the temperature of the reaction. Since the enthalpy change (ΔH) is positive it means the reaction is endothermic. Thus, heating the container i.e increasing the temperature will favours the forward reaction i.e more products will be obtained.

NOTE: Pressure has no effect in the reaction system since there is no gaseous reactants.

Considering the options given above, C and E gives the correct answer to the question.

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Infrared radiation A) Heat from warm objects, used to detect the location of objects Microwaves B) All the radiation humans can

Kazeer [188]

Answer:

Infrared radiation → A) used to detect the location of objects

Microwaves → D) Used in radar and to heat food

Ultraviolet light → C)Given off by very hot objects, such as the sun Heat from warm objects

Visible light → B) All the radiation humans can see, ranging from red to violet

Explanation:

Microwaves have magnetic waves with very long lengths, greater than that of infrared light. These waves are produced through vibrations that produce heat, as the microwave is turned on, which allows the food to be heated. These waves are also used to provide communication on some types of devices.

Infrared radiation is a type of non-ionizing radiation that has a low frequency and therefore cannot be visualized, since it is not within a visible electromagnetic spectrum, having a frequency lower than red. It can be used to detect the licalization of objects and does not pose a health risk.

Ultraviolet radiation is extremely harmful to our body. It is characterized by radiation with very small wavelengths, less than 400nm. This type of radiation can be released by the sun and ultraviolet lamps.

Visible light refers to the simplest form of electromagnetic wave and covers all the radiation that our eyes can see, allowing different colors to be seen in the objects we observe according to the reorganization of atoms and molecules.

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3 years ago

If a precipitation reaction occurs, what will be the products of the unbalanced

levacccp [35]

Answer:

${ \sf{B. \: AgCl _{(s)} + NaNO _{3(aq)}}}$

Explanation:

Silver chloride precipitates out because it has a low value of Ksp.

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4 years ago

What do you wrap your sandwich in? (pun, answer must be from the periodic table)

Oxana [17]

How about P-La-S-Ti-C W-Ra-P?

8 0

4 years ago

If a reaction releases 675,000 Joules, how many kcal does it release?

Mamont248 [21]

Answer: If a reaction releases 675,000 Joules then it means it releases 161.328872 kcal.

Explanation:

According to the standard conversion,

$1 Joule = 0.000239006 kcal$

Therefore, 675,000 Joules will be converted into kcal as follows.

$1 Joule = 0.000239006 kcal\\675,000 J = 675000 J \times \frac{0.000239006 kcal}{1 J}\\= 161.328872 kcal$

Thus, we can conclude that if a reaction releases 675,000 Joules then it means it releases 161.328872 kcal.

5 0

3 years ago

1). If the molarity of a KCl (potassium chloride) solution is 8.0 M, which of these is true?

Olin [163]

Q. No. 1 is Incomplete.

___________________________________________

Q. No.2: A saline solution contains 0.015 mol NaCl in exactly 0.10 L of solution. What is the molarity of the solution?

Answer:

Molarity = 0.15 mol.L⁻¹ (or) 0.15 M

Solution:

Molarity is the the unit of concentration and it is expressed as the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution (1)

Data Given;

Moles = 0.015 mol

Volume = 0.10 L

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.015 mol ÷ 0.10 L

Molarity = 0.15 mol.L⁻¹ (or) 0.15 M

___________________________________________

Q. No.3: A solution is prepared by dissolving 42.23 g of NH₄Cl into enough water to make 0.500 L of solution. Calculate its molarity.

Answer:

Molarity = 1.578 mol.L⁻¹ (or) 1.578 M

Solution:

Data Given;

Mass = 42.23 g

Volume = 0.50 L

M.Mass of NH₄Cl = 53.49 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 42.23 g / 53.49 g.mol⁻¹

Moles = 0.789 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.789 mol ÷ 0.50 L

Molarity = 1.578 mol.L⁻¹ (or) 1.578 M

___________________________________________

Q. No.4: Determine the concentration of a solution made by dissolving 10.0 g of sodium chloride (NaCl) in 0.75 L of solution.

Answer:

Molarity = 0.228 mol.L⁻¹ (or) 0.228 M

Solution:

Data Given;

Mass = 10.0 g

Volume = 0.75 L

M.Mass of NaCl = 58.44 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 10.0 g / 58.44 g.mol⁻¹

Moles = 0.171 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.171 mol ÷ 0.75 L

Molarity = 0.228 mol.L⁻¹ (or) 0.228 M

___________________________________________

Q. No.5: Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl₂) in 0.30 L of solution.

Answer:

Molarity = 1.32 mol.L⁻¹ (or) 1.32 M

Solution:

Data Given;

Mass = 44.0 g

Volume = 0.30 L

M.Mass of CaCl₂ = 110.98 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 44.0 g / 110.98 g.mol⁻¹

Moles = 0.396 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.396 mol ÷ 0.30 L

Molarity = 1.32 mol.L⁻¹ (or) 1.32 M

8 0

4 years ago

Which change will cause more CO2 to form in a closed container?​

Which change will cause more CO2 to form in a closed container?