1meter/10 milimeters which should be 1000 mm
1m=1000mm
<span>International System of Units (SI Units) are organized body of measurements for physical quantity. They are set to be the norm or global norm scaling for every physical quantity which includes kilogram, meter, second, ampere, kelvin, candela and mole. These measurements then can increase or decrease by the power of ten, multiplied or divided. As said and explained, the SI is helpful in describing objects because </span>
<span><span>1. </span>They give us the idea of how much matter is contained in that single substance or the current state the matter is in or how hot or cold. We measure and can quantify the quality of the specific matter.</span> <span><span>
2. </span>SI Units are a global set of measurement hence, we can communicate with ease from western to eastern countries with these measurements without having problems in terms of portraying or displaying a set of physical quantities.</span>
Answer:
the answer is the 2nd option
Explanation:
distance is divided by rime
Answer:
B
Explanation:
This is because exothermic reactions occurs when bnds are formed, and involves the release of energy.
Endothermic reaction occur when bonds are broken,and involves absorption of energy.
Answer:
2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation
moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles
moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2
Propanol is limiting based on the mol ratio in balance equation of 2 : 9
To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.
moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used
moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left
mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over
<h3><u>Answer; </u></h3>
=10.38 moles KOH
<h3><u>Explanation</u>;</h3>
The balanced equation.
6KOH + Al2(SO4)3 --> 3K2SO4 + 2Al(OH)3
From the equation;
1 mole of aluminum sulfate requires 6 moles of potassium hydroxide.
Moles of Aluminium sulfate; 1.73 moles
Moles of KOH;
1 mol Al2(SO4)3 : 6 mol KOH = 1.73 mol Al2(SO4)3 : x mol KOH
Thus; x = (6 × 1.73)
<u> =10.38 moles KOH </u>
