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Ilya [14]
3 years ago
9

-5 - -2 plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz helppppppppppppppppppppppppppppppp meee

eeeeeeeeeeeeeeeeeeeeeee
Chemistry
2 answers:
julia-pushkina [17]3 years ago
5 0

Answer:

-3

Explanation:

if we have 2 negative signs together , it equals positive

so

-5-(-2) is basically -5+2

and -5+2= -3

the image below might help and feel free to ask for further assistance

Zepler [3.9K]3 years ago
4 0
The answer would be -3
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Evaluate ( a=2 b=3)...3a - 2b =​
skad [1K]

Hey!

---------------------------------------------------

Steps To Solve:

~Substitute

3(2) - 2(3)

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6 - 6

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\Large\boxed{\mathsf{0}}

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4 0
3 years ago
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How many alcohols and ethers share the molecular formula c2h6o?
Nadya [2.5K]

Answer is: there are two compounds with molecular formula C₂H₆O, one alcohol and one ethar.

Alcohol with molecular formula C₂H₆O is ethanol or ethyl alcohol (C₂H₅OH).

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4 0
3 years ago
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Oil doesn't mix with water because
puteri [66]
<span>Oil and water don't mix because oil is made up of non-polar molecules while water molecules are polar in nature. Because water molecules are electrically charged, they get attracted to otherwater molecules and exclude the oil molecules. (this is from wiki)</span>
5 0
3 years ago
At-57 °C and 1 atm, carbon dioxide is in which phase? View Available Hint(s) Phase diagrams for water (Figure 1)and carbon dioxi
goblinko [34]

Answer:

Gas

Increase the pressure

Explanation:

Let's refer to the attached phase diagram for CO₂ (not to scale).

<em>At -57 °C and 1 atm, carbon dioxide is in which phase?</em>

If we look at the intersection between -57°C and 1 atm, we can see that CO₂ is in the gas phase.

<em>At 10°C and 2 atm carbon dioxide is in the gas phase. From these conditions, how could the gaseous CO₂ be converted into liquid CO₂?</em>

Since at 10°C and 2 atm carbon dioxide is below the triple point, the only way to convert it into liquid is by increasing the pressure (moving up in the vertical direction).

4 0
3 years ago
When 0.250 moles of KCl are added to 200.0 g of water in a constant pressure calorimeter a temperature change is observed. Given
777dan777 [17]

Explanation:

Upon dissolution of KCl heat is generated and temperature of the solution raises.

Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.

             17.24 kJ/mol \times 0.25 mol

                = 4.31 kJ

or,             = 4310 J      (as 1 kJ = 1000 J)

Mass of solution will be the sum of mass of water and mass of KCl.

       Mass of Solution = mass of water + (no. of moles of KCl × molar mass)

                                    = 200 g + (0.25 mol \times 54.5 g/mol)

                                    = 200 g + 13.625 g

                                    = 213.625 g

Relation between heat, mass and change in temperature is as follows.

                             Q = mC \Delta T

where,    C = specific heat of water = 4.184 J/g^{o}C

Therefore, putting the given values into the above formula as follows.

                     Q = mC \Delta T

            4310 J = 213.625 g \times 4.184 J/g^{o}C \times \Delta T      

              \Delta T = 4.82^{o}C

Thus, we can conclude that rise in temperature will be 4.82^{o}C.

6 0
3 years ago
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