Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv
Substitute the suitable values in the above equation.
v₁ = 2.57 m/s
Microwave s to heat up food in my microwave
that's one
Answer:
Explanation:
Using ohm's law
a) V = IR where V is voltage in Volt, I is current in Ampere and R is resistance in ohms
R = V / I = 1.50 V/ ( 2.05 /1000) A = 731.71 ohms
b) Power = IV = 
× v = 
= 
= 0.1107 W
c) E = IR + Ir = ( 731.71 × 0.0036) + ( 35 × 0.0036) = 2.76 V
d) Power use by the resistor = I²R = 0.0036² × 731.71 = 0.00948 W = 0.00948 W = 0.000009483 kw × ( 18 / 60 ) H = 2.84 × 10⁻⁶ KW-H
Their "airspeeds" (speed through the air) are equal, but the one traveling in the
same direction as the jet-stream appears to move along the ground faster.
Answer:
Answer:
f) The puck conserves its original momentum but loses some, but not all, of its mechanical energy.
Explanation:
It is a case of perfectly inelastic collision . So momentum will be conserved because no external force acts on them during the collision . But there will be loss of energy ( kinetic energy ) . It will be in the form of sound or heat that is produced during collision. They will still have some kinetic energy even after the collision.
Explanation:
