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2 years ago

What Period would this element be in?

Chemistry

1 answer:

AlladinOne [14]2 years ago

5 0

Answer:

Period 2

Explanation:

From the picture provided, I am guessing this is Fluorine. Normal Fluorine has 9 protons, electrons, and atomic number. Thus, it can be found in the second period.

***Period # = # of electron shells

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At a certain temperature the rate of this reaction is first order in SO₃ with a rate constant of 0.208 s⁻¹:

NNADVOKAT [17]

Answer:

0.30 M

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t = ?

$[A_0]$ is the initial concentration = 1.36 M

k is the rate constant = 0.208 s⁻¹

t = 7.30 seconds

So,

$[A_t]=1.36\times e^{-0.208\times 7.30}\ M=0.30\ M$

8 0

2 years ago

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amm1812

What do you mean bro

7 0

3 years ago

PLEASE HELPPPPPPPPPPPPPP

melamori03 [73]

It changes from a liquid from to a solid.

I hope this helps!

3 0

2 years ago

Which action is necessary for a solar eclipse to occur?

Nat2105 [25]

Answer:

Moon has to be in-between the Earth and the Sun.

2. Moon's umbra should sweep your place.

3. Latitude and longitude of your place should be within the befitting limits.

6 0

2 years ago

What is the molality of a solution that contains 1.34 moles of NaCl in 2.47 kg of solvent

dsp73

The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

$\text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}$

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

Hence, $\text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}$

Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

8 0

3 years ago