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lord [1]
3 years ago
5

A substance with a definite shape and volume is in which state of matter?

Physics
2 answers:
krok68 [10]3 years ago
8 0

Answer Solid is the state in which matter maintains a fixed volume and shape; liquid is the state in which matter adapts to the shape of its container but varies only slightly in volume; and gas is the state in which matter expands to occupy the volume and shape of its container.

Explanation:

Fynjy0 [20]3 years ago
8 0

Answer: Solid

Explanation: A solid has definite volume and shape, a liquid has a definite volume but no definite shape, and a gas has neither a definite volume nor shape. The change from solid to liquid usually does not significantly change the volume of a substance.

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A cat is dropped out of a window and falls to the ground in 12 seconds. It lands on its feet.
zloy xaker [14]

Answer:

The impact was gravity

Explanation:

LOOK IT UP SIS

4 0
3 years ago
In one type of mass spectrometer, ions having the same velocity move through a uniform magnetic field. The spectrometer is being
Sati [7]

Answer:

 r = 0.5297 m

Explanation:

In this exercise we use Newton's second law where the force is magnetic

         F = ma

centripetal acceleration

          a = v² / r

          F = q v x B = q v B sin θ

where the angle between the velocity and the magnetic field is 90º, therefore the sin 90 = 1

we substitute

          q v B= m v² / r

          r = \frac{m v^2 }{qv B}

the mass of each isotope is

12C

          m12 = 6 m_proton + 6 m_neutrons

          m12 = (6 1,673 +6 1,675) 10⁻²⁷

          m12 = 20.088 10-27 kg

14C

          m14 = 6 m_proton + 8 m_neutron

          m14 = (6 1,673 + 8 1,675) 10-27

          m14 = 23,438 10⁻²⁷ kg

in the exercise they indicate that the velocity of the two particles is the same, therefore with the initial data we can calculate the parameters that do not change in the experiment.

           \frac{v}{qB}  = \frac{r}{m_{12}}

           v / qB = 0.454 / 20.088 10⁻²⁷

           v / qb = 2.26 10²⁵

this quantity remains constant, let's use the other data to calculate the radius

          r = 23.438 10⁻²⁷   2.26 10²⁵

         r = 5.297 10⁻¹ m

         r = 0.5297 m

7 0
3 years ago
A piece of thin uniform wire of mass m and length 3b is bent into an equilaeral triangle.
Nookie1986 [14]

Answer: Option (C) is the correct answer.

Explanation:

Formula for moment of inertia is as follows.

                 M.I = \frac{mass \times (length)^{2}}{3}

Hence, moment of inertia of two rods is as follows.

      M.I of two rods = 2 \times \frac{(\frac{m}{3} \times b^{2})}{3}

                                = \frac{2mb^{2}}{9}    

As third rod have no connection with vertices. So, moment of inertia of a rod along an axis passing through its center is as follows.

           M.I = \frac{mass \times (length)^{2}}{12}

                 = \frac{mb^{2}}{3 \times 12}

                 = \frac{mb^{2}}{36}

Using parallel axis theorem moment of inertia through vertices is as follows.

  \frac{mb^{2}}{36} + mass \times \text{distance between the two axes}

       h^{2} = b^{2} - \frac{b^{2}}{4}

                  = \frac{3b^{2}}{4}

                h = \frac{\sqrt{3b}}{2}

Now, we will calculate the moment of inertia of third rod about vertices is as follows.

        \frac{mb^{2}}{36} + [(\frac{m}{3}) \times 3\frac{b^{2}}{4}]

            = mb^{2}[\frac{1}{36} + \frac{1}{4}]

            = 5 \frac{mb^{2}}{18}

Therefore, total moment of inertia is calculated as follows.

            Total M.I = \frac{2mb^{2}}{9} + \frac{5mb^{2}}{18}

                            = \frac{mb^{2}}{2}

Thus, we can conclude that the moment of inertia of the wire triangle about an axis perpendicular to the plane of the triangle and passing through one of its vertices is \frac{mb^{2}}{2}.

4 0
4 years ago
The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60 cm ) sin ( 6.20 y+ 60.0 t ), where y is in m
trapecia [35]

Answer:

The question is incomplete, below is the complete question

"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.

A) What is the frequency of this wave?

B)  What is the wavelength of this wave?

C) What is the speed of this wave?"

Answers:

a.  f=\frac{30}{\pi }Hz\\

b. wavelength=\frac{\pi }{3.1}m \\

c. v=9.68m/s

Explanation:

The equation of a wave is represented as

D(x,t)=Asin(kx+wt) \\

Where A=amplitude

w=angular frequency=2πf

K=wave numbers =2π/λ

since we re giving he equation  D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),

we can compare and get the value for the wave number and angular frequency.

By comparing we have

w=60rads/s

k=6.20

a. to determine the frequency, from the expression fr angular wave frequency we have

w=2πf hence

f=w/2π

if we substitute we arrive at

f=\frac{60}{2\pi }\\f=\frac{30}{\pi }Hz\\

b. to determine the wave length, we use

k=\frac{2\pi }{wavelength} \\k=6.2\\wavelength=\frac{2\pi }{k} \\wavelength=\frac{2\pi }{6.2} \\wavelength=\frac{\pi }{3.1}m \\

c. the wave speed  v is express as the product of the frequency and the wavelength. Hence

v=frequency*wavelength \\v=\frac{30}{\pi } *\frac{\pi }{3.1}\\ v=9.68m/s

6 0
3 years ago
At its nearest, Venus comes within about 41 million km of Earth. How distant is it at its farthest?
mariarad [96]

Answer:

261 million km

Explanation:

Venus has an almost perfectly circular orbit with 0.007 eccentricity. Earth however has an elliptical orbit with 0.016 eccentricity. Distance of Earth from Venus at its farthest is 261 million km. So, the difference in the farthest and closest distance is very high almost 220 million km. At the farthest Venus is 108,939,000 km from the sun and 107,477,000 km at its closest from the Sun.

5 0
3 years ago
Read 2 more answers
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