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3 years ago

What is the advantages and disadvantages of 'howe' truss?

Physics

1 answer:

Vinvika [58]3 years ago

6 0

Answer:

Advantages: Very sturdy, can have several cracks in structure before breaking

disadvantages: best for short distances, not attractive, hard to maintain

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The magnitudes of the charge densities on the inner and outer shells are now changed (keeping λinner = -λouter) so that the resu

elena-14-01-66 [18.8K]

Answer: a) Cnew=Cinitial ; b) λouter new= 2*λ outer initial

Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:

C/L= (2*π*εo)/ln (b/a)= where b and a are the outer and inner radius, respectively. L is the length of the capacitor.

As you can se this formule depents of geometrical characateristics of the capacitor.

The capacitance is the same after change the densities of charge.

On the other hand,

The new charge in each cylinder ( inner and outer) is determined

The new potential is 2 times the initial one so

V new= 2* Vinitial

Also we know that

Vnew= Q/C= λnew*L/C; C= constant

using this formule and considering that V new is doubled then the charge per one meter length, is also doubled .

This is as follow:

Vnew= λnew*L/C=

λnew = (2*Vinitial)* C/L= 2 (λ initial)

Then λouter new = 2* λouter initial

5 0

3 years ago

do u ever think that how are u living cause we could not even be here and God but made us but had did it all started I believe i

Katena32 [7]

Answer:

What is the question

Explanation:

lol

5 0

3 years ago

The kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.

eimsori [14]

E=(mV^2)/2
m=1000kg, V=20m/s
then, E=(1000kg*(20m/s)^2)/2
E=(1000*400)/2 J = 200000J

8 0

3 years ago

A(n) 12500 lb railroad car traveling at 7.8 ft/s couples with a stationary car of 7430 lb. The acceleration of gravity is 32 ft/

navik [9.2K]

To solve this problem we will apply the concepts related to the conservation of momentum. That is, the final momentum must be the same final momentum. And in each state, the momentum will be the sum of the product between the mass and the velocity of each object, then

$\text{Initial Momentum} = \text{Final Momentum}$

$m_1u_1 +m_2u_2 = m_1v_1+m_2v_2$

Here,

$m_{1,2}$ = Mass of each object

$u_{1,2}$ = Initial velocity of each object

$v_{1,2}$ = Final velocity of each object

When they position the final velocities of the bodies it is the same and the car is stationary then,

$m_2u_2 = (m_1+m_2)v_f$

Rearranging to find the final velocity

$v_f = \frac{m_2u_2}{ (m_1+m_2)}$

$v_f = \frac{ 12500*7.8}{ 12500+7430}$

$v_f = 4.8921ft/s$

The expression for the impulse received by the first car is

$I = m_1 (v-u)$

$I = \frac{W}{g} (v-u)$

Replacing,

$I = \frac{12500}{32.2}(4.89-7.8)$

$I = -1129.65lb\cdot s$

The negative sign show the opposite direction.

7 0

3 years ago

A hot air balloon is filled with 1.45 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 109 ∘ C . Wha

just olya [345]

Answer:

The volume of air after the balloon is heated = 1.95 × 10⁶ L

Explanation:

Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁)T₂.................... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.

Substituting these values into equation 1 above,

V₂ = (1.45×10⁶)382/284

V₂ = 1.95 × 10⁶ L

Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L

6 0

3 years ago