Science- look at the picture and i will mark you as brainlyliset if you answer correctly.
2 answers:
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Answer:
T =176 N
Explanation:
from diagram
F -(m_1+m_2_g) = (m_1+m_2_g)a
440 - (6+4)g = (6+4)a
a =\frac{440-10*9.8}{10}
a =34.2 m/s^2
frrom free body diagram of mass m2 = 4kg
T -m_2g =m_2a
T = m_2(g +a)
T = 4(9.81+34.2)
T =176 N
Answer:
6 m/s is the missing final velocity
Explanation:
From the data table we extract that there were two objects (X and Y) that underwent an inelastic collision, moving together after the collision as a new object with mass equal the addition of the two original masses, and a new velocity which is the unknown in the problem).
Object X had a mass of 300 kg, while object Y had a mass of 100 kg.
Object's X initial velocity was positive (let's imagine it on a horizontal axis pointing to the right) of 10 m/s. Object Y had a negative velocity (imagine it as pointing to the left on the horizontal axis) of -6 m/s.
We can solve for the unknown, using conservation of momentum in the collision: Initial total momentum = Final total momentum (where momentum is defined as the product of the mass of the object times its velocity.
In numbers, and calling the initial momentum of object X and
the initial momentum of object Y, we can derive the total initial momentum of the system:
Since in the collision there is conservation of the total momentum, this initial quantity should equal the quantity for the final mometum of the stack together system (that has a total mass of 400 kg):
Final momentum of the system:
We then set the equality of the momenta (total initial equals final) and proceed to solve the equation for the unknown(final velocity of the system):