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kodGreya [7K]
3 years ago
8

An object is moving with constant non-zero acceleration in the +x direction. The velocity versus time graph of this object is wh

at shape? A) a vertical straight line or D) a parabolic curve​
Physics
1 answer:
Katarina [22]3 years ago
5 0

Answer:

A

Explanation:

a= constant

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Molecules in a gas move faster than in a liquid.

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3 years ago
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A signal source that is most conveniently represented by its Th´evenin equivalent has vs = 10 mV and Rs = 1 k. If the source fee
gogolik [260]

Answer:

RL=100K → Vo=9.90 mV

RL=10K → Vo=9.09 mV

RL=1K → Vo=5 mV

RL=100 → Vo=909.09 μV

In order to obtain 80% of the power source we have to put a resistor of 4 KOhm.

Explanation:

Here we have a power source in serie with a resistor of 1K and  RL, in order to obtain the Vo voltage we have to apply the voltage divider rule, that states:

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Substituing the resistor values of RL we obtained the following results:

RL=100K → Vo=9.90 mV

RL=10K → Vo=9.09 mV

RL=1K → Vo=5 mV

RL=100 → Vo=909.09 μV

In order to find the lowest value that gives us 80% of the source voltage we have to use the voltage divider rule again and make the Vo equal to 0.8 Vin:

0.8*Vin=Vin*\frac{RL}{RL+R1}

The result of the last equation is 4000, so in order to obtain 80% of the power source we have to put a resistor of 4 KOhm.

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3 years ago
charles law states that at a constant pressure , the volume of a given amount of gas is _____ to its absolute temperature.
IRINA_888 [86]

CHARLES'S LAW

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The correct answer is 
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In fact, electric charge is quantized: the elementary charge is the charge of the electron, </span>e=1.6 \cdot 10^{-19} C, and every particle can only have an electric charge which is an integer multiple of this value. Of the options listed above, only option (3) is an integer multiple of the elementary charge: in fact, it corresponds to 2 times the electron charge:
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Why is it harder to get something moving than to keep it moving?
vovikov84 [41]

Answer:

momentum

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when something starts rolling momentum keeps it going.

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3 years ago
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