Answer
100% - double
200% - triple
300% - 4X
For a 300% increase the KE must be 4 time as large
KE2 / KE1 = M V2^2 / M V1^2 = (V1 / V2)^2 = 4
So V2 = 2 V1 for the requested increase
M V2 / M V1 = V2 / V1 = 2
So the momentum would double for a 100% increase
Answer:
V = 346.15 Volts
Explanation:
Given that,
Diameter of the sphere, d = 0.390 cm
Radius, r = 0.195 cm
Charge,
The electric potential near its surface is given by :
So, the potential near its surface is equal to 346.15 V.
A net force acting on an object causes the object to accelerate.
That much is totally true.
The direction of the acceleration is the direction of the net force.
Answer:
1)m=89.01 g
2)V(max) = 97.3 cm/s
Explanation:
Given that
K= 15 N/m
The maximum amplitude ,A=7.5 cm = 0.075 m
Given that 31 oscillations in 15 seconds ,this means that frequency f
f=\dfrac{31}{15}
f=2.066 Hz
lets take mass of the ball = m kg
m=0.08901 kg
m=89.01 g
The maximum speed
V(max)= ω x A
ω = 2π f= 2 x π x 2.066 = 12.98 rad/s
V(max) = 12.98 x 0.075 =0.973 m/s
V(max) = 97.3 cm/s
Answer:
R = 73.25 m
Explanation:
We have,
Initial speed of the ball is 27 m/s
It is projected at an angle of 40 degrees
The maximum range of the ball is given by :
Plugging all the values we get :
So, the maximum range of the ball is 73.25 m