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Levart [38]
3 years ago
8

Which is the formula for diarsenic pentoxide?

Chemistry
1 answer:
Andre45 [30]3 years ago
4 0
The formula is As205
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Which of earth's spheres consists of all living things?
Lady bird [3.3K]

"lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air)

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3 years ago
What is the molar solubility of nickel(II) sulfide in 0.091 M KCN? For NiS, Ksp = 3.0 × 10 –19; for Ni(CN) 4 2–, Kf = 1.0 × 10 3
Marta_Voda [28]

Answer:

The value is  x =  0.0227  \  M

Explanation:

From the question we are told that

     The concentration of KCN \ \ i.e \ \ CN^{-} is  M_1 = 0.091 \  M

     The solubility product constant for NiS is  K_{sp} =  3.0 *10^{-19}

     The stability  constant for Ni(CN)_4 ^{2-} is  K_f =  1.0 *10^{31}

Generally the dissociation  reaction for NiS is  

       Ni S  \underset{}{\stackrel{}{\rightleftharpoons}}   Ni^{2+} + S^{2-}

Generally the formation reaction for Ni(CN)_4 ^{2-}   is  

      4CN^-  + N_i ^{2+}  \underset{}{\stackrel{}{\rightleftharpoons}}  \ Ni(CN)^{2-}_{4}

Combining both reaction we have

      4CN^ -  + NiS  \  \underset{}{\stackrel{}{\rightleftharpoons}} \   Ni(CN)^{2-}_4 + S^{2-}

Gnerally the equilibrium constant for this reaction is  

         K_c  =  K_{sp} * K_f

=>       K_c  = 3.0 *10^{-19 } * 1.0 *10^{31}  

=>       K_c  = 3.0*10^{12}

Generally the I C E  table for the above reaction is  

                     4CN^ -  \ \ \  + \ \ \ NiS  \ \ \ \ \ \ \  \underset{}{\stackrel{}{\rightleftharpoons}} \ \ \ \ \    Ni(CN)^{2-}_4 \ \ \ \ \ \ \ \ \ + \ \ \ \ \  \ \ \ \ S^{2-}

initial [ I]        0.091                                              0                                    0

Change [C]        -4x                                                 +x                                    + x

Equilibrium [E ]   0.091 - 4x                                      x                                        x

Here is  x is the amount in term of concentration that is lost by CN^-  and gained by   Ni(CN)_4 ^{2-}  and  S^{2-}

Gnerally the equilibrium constant for this reaction is mathematically represented as

              K_c  =  \frac{[Ni (CN)_4^{2-} ] [S^{2-} ] }{ [CN^{-}]^4}

=>             3.0*10^{12} =  \frac{x *  x}{ [0.091 - 4x ]^4}

=>              3.0*10^{12}*  [0.091 - 4x ]^4 = x^2

=>              [0.091 - 4x ]^4 =  \frac{x^2}{3.0*10^{12}}

=>              [0.091 - 4x ] = \sqrt[4]{ \frac{x^2}{3.0*10^{12}}}

=>              [0.091 - 4x ] = \frac{\sqrt{x} }{1316}

=>              119.8 - 5264x =\sqrt{x}

Square both sides

                 (119.8 - 5264x)^2 =x

=>               14352.04 - 1261255 x + 27709696x^2 = 0

=>                27709696x^2  - 1261255 x + 14352.04  = 0

Solving using quadratic equation

   The value of x  is  x =  0.0227  \  M

Hence the amount in terms of  molarity (concentration) of  Ni(CN)_4 ^{2-}  and  S^{2-} produced at equilibrium is x =  0.0227  \  M it then means that the amount of  NiS (nickel(II) sulfide) lost at equilibrium is  x =  0.0227  \  M

So the molar solubility of nickel(II) sulfide at equilibrium is  

        x =  0.0227  \  M

           

3 0
3 years ago
How can you figure out how much energy your body gets from the food you eat and drink in a day?
noname [10]
It gets all the energy from food food is every important
6 0
3 years ago
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How many grams of water can be formed when 80 grams of sodium hydroxide (NaOH) reacts with an excess of sulfuric acid, H2SO4, in
podryga [215]

Answer:

36g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction:

2NaOH + H2SO4 —> Na2SO4 + 2H2O

Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation. This is illustrated below:

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g.

From the balanced equation above, we can see evidently that:

80g of NaOH reacted to produce 36g of H2O.

5 0
3 years ago
The theater director offered every member of the drama one vote for which play they preferred to perform. The director found tha
irakobra [83]
<h2>ANSWER:</h2>

Yes, in this group both events "Oddems Family" and "Thirteenth Night" are mutually exclusive.

<h3>Explanation:</h3>

Mutually exclusive is an statistical term which means the probability of occurrence of two separate event at the same time is zero. It means two events can not be occurred simultaneously.

For example, if we roll the deck ant the probability of coming 1 and 6 at the same time is zero and both events do not depends upon each others occurrence.

Hence only one drama can run in theater at one time. So they are mutually exclusive events.

3 0
3 years ago
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