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3 years ago

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Chemistry

2 answers:

Vlad1618 [11]3 years ago

8 0

Answer: option B.

carbon + oxygen → carbon dioxide

Explanation:

arlik [135]3 years ago

7 0

Option b
Carbon+ oxygen-> carbon dioxide

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2A (g) + Y (g) <-- --> 3C (g) + D (g)

insens350 [35]

Answer:

A. K = 59.5

Explanation:

Hello there!

In this case, since this reaction seems to start moving leftwards due to the fact that neither A nor Y are present at equilibrium, we should rewrite the equation:

3C (g) + D (g) <-- --> 2A (g) + Y (g)

Thus, the equilibrium expression is:

$K^{left}=\frac{[A]^2[Y]}{[C]^3[D]}$

Next, according to an ICE table for this reaction, we find that:

$[A]=2x$

$[Y]=x$

$[C]=0.651M-3x$

$[D]=0.754M-x$

Whereas x is calculated by knowing that the [C] at equilibrium is 0.456M; thus:

$x=\frac{0.651-0.456}{3} =0.065M$

Next, we compute the rest of the concentrations:

$[A]=2(0.065M)=0.13M$

$[Y]=0.065M$

$[D]=0.754M-0.065M=0.689M$

Thus, the equilibrium constant for the leftwards reaction is:

$K^{left}=\frac{(0.13M)^2(0.065M)}{(0.456M)^3(0.689M)}=0.0168$

Nonetheless, we need the equilibrium reaction for the rightwards reaction; thus, we take the inverse to get:

$K^{right}=\frac{1}{0.0168}=59.5$

Therefore, the answer would be A. K = 59.5.

Regards!

6 0

3 years ago

In this redox reaction, identify the element that was reduced.

malfutka [58]

I think the correct answer from the choices listed above is the third option. <span>In the redox reaction given, the element that was reduced was Fe or iron. It's charge reduced from +3 to zero, a neutral charge. Hope this answers the question. Have a nice day.</span>

5 0

3 years ago

Read 2 more answers

22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how

Licemer1 [7]

Answer:

<h2>1.23 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{6.76 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{6.76}{6.02} \\ = 1.22923...$

We have the final answer as

<h3>1.23 moles</h3>

Hope this helps you

5 0

3 years ago

Write balanced molecular, ionic, and net ionic equations for the reaction occurs when (a) a BaCl2 (Barium Chloride) is mixed wit

lubasha [3.4K]

A.) We write the molecular equation for the chemical reaction as:

BaCl2(aq)+Na2SO4(aq)→BaSO4(s)⏐+2NaCl(aq)

Alternatively, we could write the net ionic equation:

Ba2+ + SO2^−4→ BaSO4(s)⏐

B.)We write the molecular equation for the chemical reaction as:

Ba(OH)^2 + 2HBr → BaBr2 + 2H2O

The ionic equation can be written as;

Ba^2+ + 2OH^- + 2H^+ + 2Br^- →

Ba^2+ + 2Br^- + 2H2O

the net ionic equation can be written as;

2OH^- + 2H^+ → 2H2O

Alternatively, we could write the net ionic equation

OH^-(aq) + H^+(aq) → H2O(l) net ionic equation.

C.) We write the molecular equation for the chemical reaction as:

2 HNO2(aq) + Ba(OH)2(aq) 

→ Ba(NO2)2(aq) + 2 H2O(l)

Net ionic equation

HNO2(aq) + OH-(aq) → NO2-(aq) + H2O(l)

Alternatively, we could write the net ionic equation as:

2H^+ + 2OH → 2H2O

8 0

4 years ago

On earth, an object that contain more matter than another will always have

Oksanka [162]

It will always have a greater mass

4 0

3 years ago