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Dima020 [189]
3 years ago
7

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Chemistry
2 answers:
Vlad1618 [11]3 years ago
8 0

Answer: option B.

carbon + oxygen → carbon dioxide

Explanation:

arlik [135]3 years ago
7 0
Option b
Carbon+ oxygen-> carbon dioxide
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When electromagnetic radiation above the threshold frequency falls on an object, it emits electrons? a
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<span>Electromagnetic radiation will be emitted when any object has a temperature above zero.  The reason behind this is that atoms within any object at a temperature above absolute zero have energy, and thus is moving.</span>

<span>Atoms are at least partly composed of charged particles, changed particles must be moving too.</span>

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3 years ago
In the lewis structure of ch3oh, how many bonding pairs of electrons are there?
zysi [14]
Answer:
            There are five <span>bonding pairs of electrons in Methanol.

Explanation:
                   Those electron pairs which are being shared between two atoms in molecule are called as bonding pair electrons. While, those electron pairs which are not involved in bond formation and are not shared between two atoms are called as Non-Bonding electron pairs.
                   In molecule of Methanol as shown below, it can be seen that carbon atom is forming four bonds with three hydrogen atoms and one oxygen atom by sharing four electron pairs and oxygen is forming two bonds, one with carbon atom and one with hydrogen atom. There are two lone pair of electrons present on oxygen atom which are not taking part in and formation.</span>

8 0
4 years ago
A sunscreen preparation contains 2.60 % by mass benzyl salicylate. If a tube contains 6.0 oz of sunscreen, how many kilograms of
Marrrta [24]

Answer : The mass of benzyl salicylate needed to manufacture 350 tubes of sunscreen are, 1.55 kg

Explanation :

As we are given that a sunscreen preparation contains 2.60 % by mass benzyl salicylate. That means, 2.60 grams of benzyl salicylate present in 100 g of solution.

First we have to convert the given mass from oz into kg.

Conversion used:

1 kg = 35.274 oz

or,

1oz=\frac{1}{35.274}kg

So,

6oz=\frac{6oz}{1oz}\times \frac{1}{35.274}kg=0.1701kg

Now we have to determine the mass of benzyl salicylate.

As, 100 g of solution contains mass of benzyl salicylate = 2.60 g

So, 0.1701 kg of solution contains mass of benzyl salicylate = \frac{2.60g}{100g}\times 0.1701kg=0.00442kg

Now we have to determine the mass of benzyl salicylate are needed to manufacture 350 tubes of sunscreen.

Mass of benzyl salicylate in 350 tubes of sunscreen = 0.00442 kg × 350

Mass of benzyl salicylate in 350 tubes of sunscreen = 1.55 kg

Thus, the mass of benzyl salicylate needed to manufacture 350 tubes of sunscreen are, 1.55 kg

6 0
4 years ago
How can a chemical reaction be sped up?Select from the drop-down menu to correctly complete the statement.
lakkis [162]

Answer:

A) Concentration

Explanation:

When you add a chemical to itself it becomes more concentrated making it more powerful and faster

3 0
3 years ago
Read 2 more answers
Copper exists naturally as two isotopes copper-63 with a mass of 62.93 amu and copper-65 with a mass of 64.93 amu. The average m
Andrej [43]

<u>Answer:</u> The percentage abundance of _{29}^{63}\textrm{Cu} isotope is 69 %.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i     .....(1)

We are given:

Let the fractional abundance of _{29}^{63}\textrm{Cu} isotope be 'x'

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Mass of _{29}^{63}\textrm{Cu} isotope = 62.93 amu

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = x

  • <u>For _{29}^{65}\textrm{Cu} isotope:</u>

Mass of _{29}^{65}\textrm{Cu} isotope = 64.93 amu

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = (1-x)

  • Average atomic mass of copper = 63.55 amu

Putting values in above equation, we get:

63.55=[(62.93\times x)+(64.93\times (1-x))]\\\\x=0.69

Converting this fractional abundance into percentage abundance by multiplying it by 100, we get:

\Rightarrow 0.69\times 100=69\%

Hence, the percentage abundance of _{29}^{63}\textrm{Cu} isotope is 69 %.

8 0
4 years ago
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