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skad [1K]
3 years ago
13

Two people are trying to pull a 5-kilogram block in opposite directions. The first person pulls to the right with a force of 25

Newtons, and the second person pulls to the left with a force of 15 Newtons. What is the acceleration of the block?
Question 9 options:

8ms2to the right


2 ms2 to the right


2ms2to the left


10 N to the right
Physics
1 answer:
klasskru [66]3 years ago
7 0

TEST TEST TEST TEST TEST TEST TEST

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List some limiting factors that might limit the size of a population within its environment
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A force of 6.0 N gives a 2.0 kg block an acceleration of 3.0
Semenov [28]

Explanation:

The Net Force of the object can be written by:

Fnet = ma

where m is the mass of the object in <em>kg</em>

a is the acceleration of the object in <em>m/s^2</em>

Hence by applying the formula we get:

Fnet = (2.0)(3.0)

= 6N

We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:

Fnet = Pushing Force + (-Friction)

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3 years ago
Dark clothing feels warmer than white clothing on a sunny day. Which interaction causes the dark clothing to feel warm?
yulyashka [42]

Explanation:

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3 years ago
Read 2 more answers
At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 6
Ilia_Sergeevich [38]
Momentum of car

Given: Mass m= 1,400 Kg;    V = 6.0 m/s

Formula:  P = mv    

                P = (1,400 Kg)(6.0 m/s)

                P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

Mass of rider and bicycle  m = 100 Kg

P = mv

V = P/m

V = 8,400 Kg.m/s/100 Kg

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2 years ago
A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will be its final velocity in m/s,
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Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

v = 33.33 + 13 x 2

v = 59.33 m/s [N]

Therefore, the final velocity of the car is 59.33 m/s [N]

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