Answer:
Explanation:
We have given the radius of first sphere is 10 cm and radius of second sphere is 20 cm
So the potential of first sphere will be greater than the potential of the second sphere, so charge will flow from first sphere to second sphere
Let q charge is flow from first sphere to second sphere and then potential become same
So 
200-100=2q+q
So 
We know that potential energy U=qV
Answer:
The ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m
Explanation:
Fringe spacing w = λ·D/s
Diffraction grating, d·sin(θ) = n·λ
n = Number of lines
When θ = 90°, we have, sin(θ) = sin(90°) = 1
Therefore;
d·sin(θ) = d × 1 = d = n·λ
When n = 6 lines and d = 550-nm, we have;
d = 6 × 550-nm = 3,300 nm = 3.3 microns = 3.3 × 10⁻⁶ m
Therefore, the ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m.
Answer:
It's due to the distance from either ends of strings origin...
Explanation:
As we know that waves behave moving in a flow from one side to another side and this gives a prospective of motion. Suppose a wave is pinched from the near one end of a guitar then due to the distortion created by the point of tie of strings the wave super imposes and moves with a velocity v and produces a wave frequency f. as we the pinching go down to the center the wave stabilizes itself to a stationary origin right at the center and the frequency then changes accordingly as moving down on the string.
Given:
L = 1 mH = 
H
total Resistance, R = 11 
current at t = 0 s,
= 2.8 A
Formula used:
Solution:
Using the given formula:
current after t = 0.5 ms = 
for the inductive circuit:
I =0.011 A
Answer:
Entropy is increasing. Entropy is decreasing.
Explanation:
The Entropy doesn't change.
