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skad [1K]
3 years ago
13

Two people are trying to pull a 5-kilogram block in opposite directions. The first person pulls to the right with a force of 25

Newtons, and the second person pulls to the left with a force of 15 Newtons. What is the acceleration of the block?
Question 9 options:

8ms2to the right


2 ms2 to the right


2ms2to the left


10 N to the right
Physics
1 answer:
klasskru [66]3 years ago
7 0

TEST TEST TEST TEST TEST TEST TEST

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Explanation:

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The_____ of a substance is the temperature at which a solid begins to liquefy
kotykmax [81]

Answer:

Melting point

Explanation:

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The rates of obesity have more than doubled for children between the ages of 6 and 11 since the middle of the twentieth century.
Illusion [34]

Answer:

True

Explanation:

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3 years ago
The mass of a hypothetical planet is 1/100 that of Earth and its radius is 1/4 that of Earth. If a person weighs 600 N on Earth,
omeli [17]

To solve this problem we will apply the Newtonian concept of gravitational acceleration produced by a planet. This relationship is given by:

g = \frac{GM}{r^2}

Where,

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius

The values given are based on the constants of the earth, so they can be expressed as

M_p = \frac{1}{100} M_e

r_p = \frac{1}{4} r_e

The relationship of gravity would then be given:

g_e = \frac{GM_e}{r_e^2}

The relationship with the new planet, from the gravity of the earth would be given

g_p = \frac{GM_p}{r_p^2}

g_p = \frac{G(1/100)M_e}{(1/4 r_e)^2}

g_p = \frac{GM_e 16}{100 r_e^2}

g_p = 0.16 \frac{GM_e}{r_e^2}

g_p = 0.16g_e

The relationship with the weight of the earth would be given as:

W_e = m*g_e = 600N

W_p = m*g_p = m(0.16g_p)

W_p = (m*g_p)(0.16)

W_p = 600*0.16

W_p = 96N

Therefore the weigh on this planet would be 96N

3 0
3 years ago
Anna Litical is practicing a centripetal force demonstration at home. She fills a bucket with water, ties it to a strong rope, a
dlinn [17]

Answer:

Explanation:

Suppose when bucket is half full it has a mass of 2 m rotating in a circle of  radius r

When Bucket is quarter full then it has a mass of m rotating in a circle of radius r.

When an object moves in a circular path then it experiences an inward force which is given by

F_1=\frac{2mv^2}{r}

where v=velocity of bucket

Force in case 2 is given by

F_2=\frac{mv^2}{r}

Thus F_1=2F_2

therefore force required in half bucket is more than force required in quarter bucket full.

6 0
4 years ago
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