Hi there!
This collision is an example of an inelastic collision since kinetic energy is lost from the collision.
We can represent this using the conservation of momentum formula:
m1v1 + m2v1 = m1vf + m2vf
Where:
m1 = blue ball
m2 = green ball
We know that the final velocity of the blue ball is 0, so:
m1v1 + m2v1 = m2vf
Rearrange to solve for the speed of the green ball:
(m1v1 + m2v1)/m2 = vf
Plug in given values:
((0.15 · 3) + (0.15 · 2)) / 0.15 = 5 m/s
Answer:
they are constantly bouncing everywhere and creating preasure
Explanation:
Honestly you should switch it up to something better cause honestly all depends on how the person was raised or the backround of them
it does not matter if your are a male or female
Larger tug force = 2*cos20 forward + 2*sin20 to the right (starboard)
<span>Smaller tug force = 1*cos15 forward + 1*sin15 to the left (port) </span>
<span>Resultant force forward = 2*cos20 + 1*cos15 = 2.8453 (4dp) </span>
<span>Resultant force to right = 2*sin20 - 1*sin15 = 0.4252 (4dp) </span>
<span>Angle of resultant force = arctan(0.4252 / 2.8453) = arctan(0.1494) = 8.5 degrees</span>
The answer is D=M/V hope it helps!!
