Ask question

Ask question

All categories

2 years ago

7

the resistor of values 6 ohm,6 ohm are connected in series and 12 ohm are connected in parallel. the equivalent resistance of th

e circuit is

1 answer:

andrezito [222]2 years ago

6 0

Answer:

The equivalent or total resistance of the circuit is 6

Explanation:

6 &6 are in series

6+6=r

r= 12

1/Rtotal= 1/12+1/2

1/Rt=2/12=1/6

Rt=6

You might be interested in

How can the direction of a tensional force be changed without diminishing the force?

RSB [31]

Given what we know, we can confirm that the tensional force of a system can in theory be changed without diminishing its force through the use of an ideal pulley.

<h3>What is an ideal pulley?</h3>

A pulley is a small wheel through which a string or chain is run.
These are used in order to change the direction of a force.
An ideal pulley would be one in which there is no friction and the pulley itself would have no mass.
Therefore, the force would be able to change directions without giving part of its force to the pulley system.

Therefore, we can confirm that the only known way to change the direction of a force without diminishing its value would be through the use of a frictionless and massless pulley system otherwise known as an ideal pulley.

To learn more about Friction visit:

brainly.com/question/13357196?referrer=searchResults

4 0

2 years ago

What is the greenhouse effect?

Zanzabum

A on that problem :)[email protected]

6 0

2 years ago

Read 2 more answers

Why do waves with high frequencies have short wavelengths

dalvyx [7]

Answer: because ν = velocity/λ where ν and λ are the frequency and wavelegth of the wave.

Explanation: In order to explain this problem we have to consider the relationship between frequency and wavelengths which are related by the velocity of the wave as follows ν*λ=v where ν and λ are the frequency and wavelegth of the wave. These parameters have an inverse proportionality.

Then, ν = velocity/λ

7 0

2 years ago

Read 2 more answers

At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienc

vaieri [72.5K]

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = $\sqrt{734.22}$

U = 27.096

U = 27.1 m/s approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

5 0

3 years ago

Consider a uniform horizontal wooden board that acts as a pedestrian bridge. The bridge has a mass of 300 kg and a length of 10

gayaneshka [121]

Answer:

F = 2123.33N

Explanation:

In order to calculate the torque applied by the left support, you take into account that the system is at equilibrium. Then, the resultant of the implied torques are zero.

$\Sigma \tau=0$

Next, you calculate the resultant of the torques around the right support, by taking into account that the torques are generated by the center of mass of the wooden, the person and the left support. Furthermore, you take into account that torques in a clockwise direction are negative and in counterclockwise are positive.

Then, you obtain the following formula:

$-\tau_l+\tau_p+\tau_{cm}=0$ (1)

τl: torque produced by the left support

τp: torque produced by the person

τcm: torque produced by the center of mass of the wooden

The torque is given by:

$\tau=Fd$ (2)

F: force applied

d: distance to the pivot of the torque, in this case, distance to the right support.

You replace the equation (2) into the equation (1) and take into account that the force applied by the person and the center of mass of the wood are the their weight:

$-Fd_1+W_pd_2+W_{cm}d_3=0\\\\d_1=6.0m\\\\d_2=2.0m\\\\d_3=3.0m\\\\W_p=(200kg)(9.8m/s^2)=1960N\\\\W_{cm}=(300kg)(9.8m/s^2)=2940N$

Where d1, d2 and d3 are distance to the right support.

You solve the equation for F and replace the values of the other parameters:

$F=\frac{W_pd_2+W_d_3}{d_1}=\frac{(1960N)(2.0m)+(2940N)(3.0m)}{6.0m}\\\\F=2123.33N$

The force applied by the left support is 2123.33 N

8 0

3 years ago