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Karo-lina-s [1.5K]
3 years ago
11

Help me please!

Physics
1 answer:
MrMuchimi3 years ago
6 0
I think it’s A
Good luck
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At high elevations or high latitudes, some of the water that falls on land does not immediately soak in , run off, evaporate or
LUCKY_DIMON [66]

Answer:

The water is stored in ice sheets and as snow

Explanation:

Temperature reduces with an increase in altitudes. The standard laps rate is 6.5°C per 1,000 m gained in elevation

At very high elevations, therefore,  the air is usually very cold such that when an elevation of 4,500 meters is reached at the equator, it is possible to observe snowfall and the water remain temporarily stored on the surface of the mountain as ice and snow

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What factors cause changes in the temperature of surface water
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Answer:

sunlight/solar radiation

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If two objects of unequal mass collide, both objects will continue to move in the direction of
gayaneshka [121]
Assuming this is an elastic collision, they go in the direction of the object with more mass
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3 years ago
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Three charges, q1 = +2.06 x 10-9 C, q2 = -3.27 x 10-9 C, and q3 = +1.05 x 10-9 C, are located on the x-axis at x1 = 0, x2 = 10.0
lisov135 [29]

Answer:

The resultant force on charge 3 is Fr= -2,11665 * 10^(-7)

Explanation:

Step 1: First place the three charges along a horizontal axis. The first positive charge will be at point x=0, the second negative charge at point x=10 and the third positive charge at point x=20. Everything is indicated in the attached graph.

Step 2: I must calculate the magnitude of the forces acting on the third charge.

F13: Force exerted by charge 1 on charge 3.

F23: Force exerted by charge 2 on charge 3.

K: Constant of Coulomb's law.

d13: distance from charge 1 to charge 3.

d23: distance from charge 2 to charge 3

Fr: Resulting force.

q1=+2.06 x 10-9 C

q2= -3.27 x 10-9 C

q3= +1.05 x 10-9 C

K=9-10^9 N-m^2/C^2

d13= 0,20 m

d23= 0,10 m

F13= K * (q1 * q3)/(d13)^2

F13=9,7335*10^(-8) N

F23=K * (q2 * q3)/(d23)^2

F23= -3,09 * 10^(-7)

Step 3: We calculate the resultant force on charge 3.

Fr=F13+F23= -2,11665 * 10^(-7)

3 0
3 years ago
Help please:A boy weighing 30 kg rides a scooter. The total kinetic energy of the boy and the scooter is 437.6 J. Determine the
Ksenya-84 [330]

Answer:

the total mass is 35 kg

k.E = 1/2 mv2

43.76 =1/2 v2

v2=2×43.76

Explanation:

v=radicls 87.52 which is equal to 9.5 m/s

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