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Montano1993 [528]
3 years ago
14

Normally, in the process of osmosis, the net flow of water molecules into or out of the cell depends upon difference in the

Chemistry
1 answer:
Misha Larkins [42]3 years ago
4 0
Tonicity (how much salt is in it)
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TRIPLE POINTS!!! I NEED HELP!!! PLEASE EXPLAIN TOO!!! What is the energy of a quantum of light with a frequency of 4.31 x 1014 1
Lelechka [254]

Answer:

The answer is

2.86 \times  {10}^{ - 19}  \: J

Explanation:

The energy of a quantum of light can be found by using the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 4.31 × 10¹⁴ Hz

We have

E = 4.31 × 10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

2.86 \times  {10}^{ - 19}  \: J

Hope this helps you

3 0
3 years ago
How many moles of aluminum are in 95.0 grams of aluminum
wlad13 [49]

Answer:

26.981538 just looked at it.

6 0
2 years ago
Lee and Celia are lab partners. While Celia pours a chemical into a graduated cylinder, some of the chemical splashes onto her a
Colt1911 [192]
I think the best answer from the choices listed above is option C. With this accident, both should be alert and do what should be done. <span> Lee should tell the teacher while Celia washes her arm with soap and water. Doing this, Celia will prevent the chemical to spread more and harm further. Telling the teacher immediately will also alert the in-charge and do what should be done.</span>
6 0
3 years ago
Which structure corresponds to the predominant form of this molecule near ph 7?
slava [35]
The correct answer is C) due to:
at pH 7 alanine molecule lose one proton from its carboxylic acid group and this proton is added to its amino group 
This structure is called Zwitter ion (which contain equal number of positive and negative charges)<span />

6 0
3 years ago
How many days have passed if 4.80 mg of calcium-47 decayed to 1.2 mg of calcium-47?
LenaWriter [7]
(1) 36 days is 8 half-life periods,
so 24mg becomes 24mg times (1/2)^8 = 24 mg/256 = 0.094 mg

(2) 9.6/1.2 = 8, which means three half-life periods went by.
At the end of 4.5 days, there were 4.8 mg
At the end of 9.0 days, there were 2.4 mg
At the end of 13.5 days, there were 1.2 mg

(3) The activity is proportional to the amount of radioactive material remaining,
so after two half-life periods, the activity should be 1/4 of what it originally was.
So the initial activity was probably 12.0 Ci
6 0
3 years ago
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