$log \: {x}^{3} + log \: 5x = 5log \: 2 - log \: \frac{2}{5} \\ \\ \therefore \: log( {x}^{3} \times 5x) = log {2}^{5} - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log 32 - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(32 \times \frac{5}{2} \bigg) \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(16 \times 5) \\ \\ \therefore \: 5{x}^{4}= 16 \times 5 \\ \\ \therefore \: {x}^{4}= {2}^{4} \\ \\ \huge \purple{ \boxed{\therefore \: {x} = 2}}$

4 0

3 years ago

If the profits in your consulting business increase by 5% one year and decrease by 3% the following year, your profits are up

Leona [35]

Let the original profits be $x. 5% increase in profits will give us:
105/100×x=$1.05x
3% reduction in new profits ill give us the latest amount to be:
97/100×1.05x
=$1.0185x
comparing our new profits to our original amount of $x we shall have new percentage increase to be:
(1.0185x-x)/x×100
=1.85%
Thus our final increase 1.85%

6 0

3 years ago

I would like to know how to solve this problem.

Darya [45]

Answer: 9

Step-by-step explanation:

$g(-5)=\frac{-5}{5}=-1\\\\(f\circ g)(-5)=f(g(-5))=f(-1)=-3(-1)+6=\boxed{9}$

8 0

2 years ago