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Semmy [17]
3 years ago
7

Two ice skaters suddenly push off against one another starting from a stationary position. The 45-kg skater acquires a speed of

0.375 m/s relative to the ice. What speed does the 60-kg skater acquire relative to the ice?
Physics
1 answer:
timama [110]3 years ago
5 0

Answer:

Speed does the 60-kg skater acquire relative to the ice = 0.281 m/s

Explanation:

Momentum is conserved in this case.

Initial momentum = Final momentum.

Initial momentum = Initial momentum of skater 1 + Initial momentum of skater 2

Initial momentum = 45 x 0 + 60 x 0 = 0 kg m/s

Final momentum = 45 x 0.375 + 60 x u = 16.875 + 60 u

Here we need to find u.

We have

                  0 = 16.875 + 60 u

                   u = -0.281 m/s

Speed does the 60-kg skater acquire relative to the ice = 0.281 m/s

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How did Archimedes measure the mass of the block of gold?
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5 0
2 years ago
‏A 50 - N x m torque acts on a wheel with a moment of inertia 150 kg x m² . If the wheel starts from rest , how long will it tak
denis-greek [22]

Answer:

t = 6.17 s

Explanation:

For a 1 revolution movement, \triangle \theta = 2\pi

Torque, \tau = 50 Nm

Moment of Inertia, I = 150 kg m^2

If the wheel starts from rest, w_{0} = 0 rad/s

The angular displacement of the wheel can be given by the formula:

\triangle \theta = \omega_0 t + 0.5 \alpha t^2................(1)

Where \alpha is the angular acceleration

\tau = I \alpha\\\alpha = \frac{\tau}{I} \\\alpha = 50/150\\\alpha = 0.33 rad/s^2

To get t, put all necessary parameters into equation (1)

2\pi = 0(t) + 0.5(0.33)t^2\\2\pi =0.5(0.33)t^2\\t^2 = \frac{4 \pi}{0.33} \\t^2 = 38.08\\t = 6.17 s

3 0
3 years ago
Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. The capacitor is
NARA [144]

Answer:

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

C=\dfrac{\varepsilon _oA}{d}

By putting the values

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U=\dfrac{1}{2}CV^2

V=Voltage difference

V=\sqrt{\dfrac{2U}{C}}

V=\sqrt{\dfrac{2\times 8.49\times 10^{-9}}{2.46\times 10^{-11}}}

V=26.27 V

V= E d

E=Electric filed

26.27 = E x 0.473 x 10⁻³

E= 55.53 x 10³ V/m

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3 years ago
A piece of wood and a piece of steel are at the same temperature; however, the steel feels hotter. This is because the steel has
Vikentia [17]
The steel traps the heat more making it hotter,you put this twice by the way.
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2 years ago
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