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Semmy [17]
4 years ago
7

Two ice skaters suddenly push off against one another starting from a stationary position. The 45-kg skater acquires a speed of

0.375 m/s relative to the ice. What speed does the 60-kg skater acquire relative to the ice?
Physics
1 answer:
timama [110]4 years ago
5 0

Answer:

Speed does the 60-kg skater acquire relative to the ice = 0.281 m/s

Explanation:

Momentum is conserved in this case.

Initial momentum = Final momentum.

Initial momentum = Initial momentum of skater 1 + Initial momentum of skater 2

Initial momentum = 45 x 0 + 60 x 0 = 0 kg m/s

Final momentum = 45 x 0.375 + 60 x u = 16.875 + 60 u

Here we need to find u.

We have

                  0 = 16.875 + 60 u

                   u = -0.281 m/s

Speed does the 60-kg skater acquire relative to the ice = 0.281 m/s

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Answer:

     v₂ = 70 m / s

Explanation:

For this exercise let's use Bernoulli's equation

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          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ +1/2 ρ v₂² + ρ g y₂

indicate that the pressure in the two points is the same, y₁ = 250 m, y₂ = 0 m, the water in the upper part, because it is a reservoir, is very large for which the velocity is very small, we will approximate it to 0 (v₁ = 0), we substitute

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         v₂ = √( 2 9.8 250)

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Answer:

Thus the time taken is calculated as 387.69 years

Solution:

As per the question:

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Now,

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