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Len [333]
3 years ago
11

Can someone please help!? i’ll mark you as brainliest

Chemistry
2 answers:
slega [8]3 years ago
6 0

Answer:

Reactants: NaBr and CA(OH)2

Products: CaBr and NaOH

Explanation:

Reactants are always on th left side of the equation and products on the right side

Ghella [55]3 years ago
5 0

Answer:

26

Explanation:

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Stirring a liquid while you are mixing in another ingredient speeds up the rate of dissolving. Question 13 options: True False
brilliants [131]

Answer:

true

Explanation:

This is because it helps distribute the particles that are being dissolved. 

8 0
3 years ago
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What evidence from the experiment shows that conduction occurred? In your answer, be sure to include the materials involved in t
velikii [3]

Answer:

Explanation:

The melting of the chocolate pieces one by one showed that it was caused by heat flowing through the foil bridge. The transfer of heat happened between the foil bridge and the chocolate pieces because they were touching each other.

5 0
3 years ago
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Write the balanced chemical equation for the reaction between aqueous sodium carbonate and
ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

7 0
3 years ago
Compared to a sample of helium at STP, the same sample of helium at a higher temperature and a lower pressure A) condenses to a
zhuklara [117]

Answer:

Option D is correct.

Explanation:

Compared to a sample of helium at STP, the same sample of helium at a higher temperature and a lower pressure because any gas at a higher temperature and a lower pressure will  behaves like  an ideal gas. for eg.

nitrogen at STP show its behavior as an ideal gas.

When pressure of a gas increased & temperature is decreased then the gas does not follow ideal gas law.

Therefore option D is correct.

4 0
3 years ago
El pH de una solución acuosa 10^-14 M de ácido acético, a 25°C, es igual a, teniendo en cuenta que Ke = 1.76x10^-5
frez [133]

Answer:

pH=14

Explanation:

Hola!

En este caso, consideramos que la disociación de ácido acético ocurre:

CH_3COOH\rightarrow CH_3COO^-+H^+

Así, mediante la solución del equilibrio ácido, podemos calcular la concentración de iones hidronio que posteriormente sirven para calcular el pH de la solución, por tal razón, debemos calcular el equilibrio dada la constante de equilibrio y por medio de la ley de acción de masas en términos del cambio x como cualquier problema de equilibrio:

Ke=\frac{CH_3COO^-][H^+]}{[CH_3COOH]}\\\\1.76x10^{-5}=\frac{x*x}{1x10^{-14}M-x}

Resolviendo para x, tenemos x=0.999x10^{-14}

Así, la concentración de hidrógeno es igual a x, por lo que el pH:

pH=-log([H^+])=-log(0.999x10^{-14})\\\\pH=14

Dicho valor tiene sentido desde que la concentración de hidrógeno es casi despreciable, por lo que se puede asumir que tiende a ser básica.

Saludos!

5 0
4 years ago
Read 2 more answers
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