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4 years ago

How does a reflecting telescope work

2 answers:

6 0

Refracting telescopes use lenses to focus the light, andreflecting telescopes use mirrors. I'll talk first about refracting ones. Refracting telescopes work by using two lenses to focus the light and make it look like the object is closer to you than it really is. Both lenses are in a shape that's called 'convex'.

irga5000 [103]4 years ago

3 0

Answer: A reflecting telescope is comprised of two lens namely the primary mirror which is attached to the tube at one end of the telescope and the secondary mirror, that is kept at the line of sight of the telescope's eyepiece containing a small magnifying lens. This two mirrors, sometimes can also be used as a mixture of convex and concave lens.

According to the law of reflection, a light incident on a plane gets reflected at a same angle.

So, in case of a reflecting telescope, focusing on an object, it allows the light to pass through the tube and strikes on the primary mirror at one end, which gets reflected back to the secondary mirror. This reflected light further gets reflected to the telescope's eyepiece, that enlarges the image and reaches to the eyes.

This is the working principle of a reflecting telescope.

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A 1000 N object is pulled along a level surface with a horizontal force of 200 N. The object moves with a constant velocity of 2

krek1111 [17]

0.2 is the value of coefficient of friction (k)

F=kN

F=horizontal force

n=Normal Force

k=coefficient of friction

k=F/N

k=200/1000

k=0.2

The ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them is known as the friction coefficient. Usually, the Greek letter mu is used to indicate it .N is the normal force, and F is the frictional force, hence F = N/N.

Due to the fact that both F and N are measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds). The coefficient of friction can have a variety of values for both static and dynamic friction. Static friction occurs when an object encounters friction that resists any applied force, keeping the object at rest until the static frictional force is released. In kinetic friction, the frictional force resists the motion of the object.

To know more about coefficient of friction visit brainly.com/question/136431

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7 0

1 year ago

The total sum of atoms in an object.

Darina [25.2K]

Answer:

Mass

Explanation:

The total sum of atoms in an object is the mass of the object. There are several ways to quantify the number of atoms in a substance.

In chemical calculations, the number of moles is a good representation of the number of atoms contained in a body.
Mass is the amount of substances a body has.
If we can sum up all the atoms in a substance, one will arrive at the mass of the substance

4 0

3 years ago

What are the seasonal changes in the weasel in florida and the weasel in wyoming

AlekseyPX

Winter weasels, also called ermines or short-tailed weasels, have coats that turn from light brown to white in the winter. The color change begins at their stomachs and works its way outward, occurring in both spring and fall. Other species, like the long-tailed weasel, may turn at least partially white as well.

The length of daylight, not temperature, prompts the color change. As a result, weasels in winter may be stark white against a brown landscape before snow starts to fall. During warmer winters, this makes them easy prey for larger predators such as foxes, martens, and badgers.

7 0

3 years ago

If you see something not being right on a project you are working-even if it isn't you doing the wrong thing-it is your ethical

AVprozaik [17]

Answer:

Is this a "true or false" question?

Explanation:

4 0

3 years ago

Read 2 more answers

"Two uniform identical solid spherical balls each of mass M and radius R" and moment of inertia about its center 2/5 MR2 are rel

adelina 88 [10]

Answer:

he sphere that uses less time is sphere A

Explanation:

Let's start with ball A, for this let's use the kinematics relations

v² = v₀² - 2g (y-y₀)

indicate that the sphere is released therefore its initial velocity is zero and when it reaches the floor its height is zero y = 0

v² = 0 - 2 g (0- y₀)

v = $\sqrt{2g y_o}$

v = $\sqrt{2 \ 9.8\ H}$

v = 4.427 √H

Now let's work the sphere B, in this case it rolls down a ramp, let's use the conservation of energy

starting point. At the highest point, before you start to move

Em₀ = U = m g y

final point. At the bottom of the ramp

Em_f = K = ½ m v² + ½ I w²

notice that we include the kinetic energy of translation and rotation

energy is conserved

Em₀ = Em_f

mg H = ½ m v² + ½ I w²

angular and linear velocity are related

v = w r

w = v / r

the momentorot of inertia indicates that it is worth

I = $\frac{2}{5}$ m r²

we substitute

m g H = ½ m v² + ½ ( $\frac{2}{5}$ m r²) ( $\frac{v}{r}$ )²

gH = $\frac{1}{2}$ v² + $\frac{1}{5}$ v² = $\frac{7}{10}$ v²

v = $\sqrt{\frac{10}{7} \ g H}$

v = $\sqrt{ \frac{10}{7} \ 9.8 \ H}$

v=3.742 √H

Taking the final speeds of the sphere, let's analyze the distance traveled, sphere A falls into the air, so the distance traveled is H. The ball B rolls in a plane, so the distance (L) traveled can be found with trigonometry

sin θ = H / L

L = H /sin θ

we can see that L> H

In summary, ball A arrives with more speed and travels a shorter distance, therefore it must use a shorter time

Consequently the sphere that uses less time is sphere A

5 0

3 years ago