Ok so we don't know the sign so it could be 4x^2-8x+60 or 4x^2-8x-60 ( if it is the first one, go to AAAAAAA if it is second one go to BBBBBBBBBBB)
to find the zero fo the function, set the fnction to zero then factor since if you had xy=0, then assume that x and y=0
AAAAAAAAAA 4x^2-8x+60=0 4(x^2-2x+15)=0 4 you get a nonreal root so the missing sign is probably a negative sign if you were to graph this one, there is no x intercept
BBBBBBBBB 4x^2-8x-60=0 4(x^2-2x-15)=0 4(x-5)(x-3)=0 x-5=0 x=5 x-3=0 x=3 3<5 smallest zero is 3
The smallest zero for your equation is either -3 or 2. Since you didn't gave us what 60 was either positive or negative, I had to write it in both forms. Which are y=4x^2-8x+60 or y=4x^2-8x-60. If your equation has it with a positive 60 then the smallest zero is 2. If your equation has it with a negative 60 then the smallest zero is -3. If you need any further explanation due to how I got the answer just let me know. (:
