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alex41 [277]
2 years ago
14

Some chemical reaction is being run inside a sealed gas cylinder. During the reaction, a gaseous product is formed. The pressure

P exerted by the gas has been measured five times. A gauge calibrated in units of psig was used Data from the measurements are provided below Table 1. Pressure measurements of the oxygen generated by chemical reaction inside a gas cylinder Run d P (psig) 21.0 20.2 20.7 21.3 20.5 8. Estimate the Type A uncertainty in these measurements. Be sure to include the units. Estimate the Type B uncertainty associated with these measurements, Be sure to include units. Determine the uncertainty in the measurement of pressure in the cylinder. Be sure to include units. State your a. answer as average +/-uncertainty.
Engineering
1 answer:
daser333 [38]2 years ago
5 0

Answer:

<em>Solution:</em>

(A). For the evaluation of Type A uncertainty data, a single repeatability test containing mean, standard deviation and degrees of freedom

<em>Mean </em>

= (21.0 + 20.2 + 20.7 + 21.3 + 20.5) / 5

= 20.74 psig

<em>Standard Deviation</em>

= (0.26-0.54-0.04 + 0.56-0.24)2/5 = 0

<em>Degrees of Freedom </em>

= n-1 = 5-1

<em>= 4 </em>

(B). For the evaluation of Type B uncertainty data, because the standard deviation is zero, therefore Type B will be uncertain.

(C). Average standard

=20.74 x 5

=<em>103.70 psig</em>

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3 years ago
At the instant under consideration, the hydraulic cylinder AB has a length L = 0.75 m, and this length is momentarily increasing
Inessa [10]

Answer:

vB = - 0.176 m/s   (↓-)

Explanation:

Given

(AB) = 0.75 m

(AB)' = 0.2 m/s

vA = 0.6 m/s

θ = 35°

vB = ?

We use the formulas

Sin θ = Sin 35° = (OA)/(AB) ⇒  (OA) = Sin 35°*(AB)

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Cos θ = Cos 35° = (OB)/(AB) ⇒  (OB) = Cos 35°*(AB)

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We apply Pythagoras' theorem as follows

(AB)² = (OA)² + (OB)²

We derive the equation

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⇒  (AB)*(AB)' = (OA)*vA + (OB)*vB

⇒  vB = ((AB)*(AB)' - (OA)*vA) / (OB)

then we have

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3 years ago
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vertical gate in an irrigation canal holds back 12.2 m of water. Find the average force on the gate if its width is 3.60 m. Repo
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Answer:

The right solution is "2625 kN".

Explanation:

According to the question,

The average pressure will be:

= density\times g\times \frac{h}{2}

By putting values, we get

= 1000\times 9.8\times \frac{12.2}{2}

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hence,

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Or,

= 2625 \ kN

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2 years ago
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