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Margaret [11]
3 years ago
11

Water drains at a constant rate through a saturated soil column with a diameter of 1.5 feet and a height of 3 feet. The hydrauli

c head is maintained at 5 feet at the top of the column and 0.81 feet at the bottom. After a period of one hour, 199 cubic inches of water has drained through the column. What is the hydraulic conductivity of the soil in the column in cubic feet per hour
Engineering
1 answer:
Debora [2.8K]3 years ago
6 0

Storm Water Design Criteria Manual — January 2016

Chapter 2 | Page | 2.3

2.6 TECHNICAL CRITERIA

The storm drainage planning and design should follow the criteria within this manual.

The following two items should be considered during the design process.

1)

Diversion of storm water away from the natural watercourse will not be allowed, except

within the property boundaries controlled by the developer under the following conditions: a)

The storm water is returned to its natural flowing watercourse prior to leaving the developer's

property, b) For watersheds greater than twenty (20) acres, a timing analysis of the existing

and diverted hydrograph must be performed to confirm that the peak flow rate has not been

increased at the point that it reenters the watercourse, as a result of the diversion.

2)

All developments shall provide adequate drainage outfall at the lower end of the site into an

existing street, alley, drainage, easements or right-of-way, or to the centerline of an existing

natural drain. Where a proposed street, storm drain, or open channel does not discharge into a

natural low or into an existing adequate drainage easement, then facilities and drainage

easements of adequate width — to contain the design discharge — shall be constructed and

dedicated to the centerline of an existing natural low within the same watershed. However,

when the natural low lies within the developer's property, the developer will only be required

to plat an easement to the centerline of the natural low; provided that the easement is able to

accommodate the facilities that will be built in conjunction with future development of that

property.

2.7 FLOODPLAIN MANAGEMENT

Floodplain management has changed over the years due to the National Flood Insurance Act

of 1968. Changes from the program included USGS maps being used with the delineation of

floodplains, HUD issuing flood insurance maps in the late 1970’s, and the founding of FEMA

in 1979. The National Flood Insurance Program was ultimately placed under FEMA. As the

City began participating in this action in the late 1970’s, flood insurance can be purchased

through insurance carriers for buildings in Bexar County.

Floodplain management is used to minimize flooding of buildings, reduce flood losses, and

improve the quality of life — and safety of the citizens of Bexar County.

2.8 IMPLEMENTATION

The provisions of this manual shall apply to any application for subdivision plat, master

development plan, capital improvement project, or building permit approval except as

otherwise provided by Chapter 35 of the UDC. A storm water management plan shall be

provided as set forth in Appendix “A” of this manual.

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A cylindrical specimen of a titanium alloy having an elastic modulus of 107 GPa (15.5 × 106 psi) and an original diameter of 3.7
Keith_Richards [23]

Answer:

the maximum length of specimen before deformation is found to be 235.6 mm

Explanation:

First, we need to find the stress on the cylinder.

Stress = σ = P/A

where,

P = Load = 2000 N

A = Cross-sectional area = πd²/4 = π(0.0037 m)²/4

A = 1.0752 x 10^-5 m²

σ = 2000 N/1.0752 x 10^-5 m²

σ = 186 MPa

Now, we find the strain (∈):

Elastic Modulus = Stress / Strain

E = σ / ∈

∈ = σ / E

∈ = 186 x 10^6 Pa/107 x 10^9 Pa

∈ = 1.74 x 10^-3 mm/mm

Now, we find the original length.

∈ = Elongation/Original Length

Original Length = Elongation/∈

Original Length = 0.41 mm/1.74 x 10^-3

<u>Original Length = 235.6 mm</u>

5 0
3 years ago
8.19 - Airline Reservations System (Project Name: Airline) - A small airline has just purchased a computer for its new automated
e-lub [12.9K]

Answer:

The App is written in C++ language using dev C++.

Explanation:

/******************************************************************************

You can run this program in any C++ compiler like dev C++ or any online C++ compiler

*******************************************************************************/

#include <iostream>

using namespace std;

class bookingSeat// class for airline reservation system

{

  private:

   

   

  bool reserveSeat[10];// 10 seats (1-5) for first class and 6-10 for economy class

  int firstClassCounter=0;//count first class seat

  int economyClassCounter=5;//count economy class seat

  char seatPlacement;/* switch between economy and first clas seat----- a variable for making decision based on user input*/

  public:  

  void setFirstClassSeat()//

  {

      if(firstClassCounter<5)// first class seat should be in range of 1 to 5

      {

          reserveSeat[firstClassCounter]=1; /*set first class seat..... change index value to 1 meaning that it now it is reserved*/

          cout<<"Your First Class seat is booked and your seat no is "<<firstClassCounter+1; //display seat number reserved

          firstClassCounter++; //increament counter

      }

      else//in case seats are ful

      {

          cout<<"\nSeats are full";

          if(economyClassCounter==10 && firstClassCounter==5)

          {

              cout<<"\n Next flight leaves in 3 hours.";

          }

          else

          {

              cout<<"\nIt’s acceptable to be placed to you in the first-class section  y/n ";//take input from user

              cin>>seatPlacement;//user input

              if(seatPlacement=='y')//if customer want to reserve seat in first class

              {

                  setEconomyClassSeat();// then reserve first class seat

              }

              else

              {

                  cout<<"\n Next flight leaves in 3 hours.";

               }

               

          }

      }

       

  }

  void setEconomyClassSeat()//set economy class seat

  {

    if(economyClassCounter<10)//seat ranges between 6 and 10

      {

          reserveSeat[economyClassCounter]=1;// reserve economy class seat

          cout<<"Your Economy class seat is booked and your seat no is "<<economyClassCounter+1;//display reservation message about seat

          economyClassCounter++;//increament counter

      }

      else// if economy class seats are fulled

      {

          cout<<"\nSeats are full";

          if(economyClassCounter==10 && firstClassCounter==5)//check if all seats are booked in both classes

          {

              cout<<"\n Next flight leaves in 3 hours.";

          }

          else

          {

              cout<<"\nIt’s acceptable to be placed to you in the first-class section  y/n ";//take input from user

              cin>>seatPlacement;//user input

              if(seatPlacement=='y')//if customer want to reserve seat in first class

              {

                  setFirstClassSeat();// then reserve first class seat

              }

              else

              {

                  cout<<"\n Next flight leaves in 3 hours.";

               }

               

          }

      }

  }

   

   

};

int main()

{   int checkseat=10;// check seat

   int classType;//class type economy or first class

   bookingSeat bookseat;//object declaration of class bookingSeat

   while(checkseat<=10)//run the application until seats are fulled in both classes

   {

       cout<<"\nEnter 1 for First Class and 2 for Economy Class ";

       cin>>classType;//what user entered

       switch (classType)//decide which seat class to be reserved  

       {

           case 1://if user enter 1 then reserve first class seat

           bookseat.setFirstClassSeat();

           break;

           case 2://if user enter 2 then reserve the economy class seat

           bookseat.setEconomyClassSeat();

           

       }

       

   }

   

   return 0;

}

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3 years ago
Water flows at low speed through a circular tube with inside diameter of 2 in. A smoothly contoured body of 1.5 in. diameter is
Art [367]

Answer:

Pressure = 11.38 psi

Force = 13.981 Ibf

Explanation:

Step by step solution is in the attached document.

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The inner surface of a hollow cylinder is subjected to tangential and axial stresses of 40,000 and 24,000 psi, respectively. Det
Furkat [3]

Answer:

15,000 psi

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The solution / solving is attach below.

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