Answer:
This is about 176 times the weight of the froghopper.
Explanation:
the grasshopper converts kinetic energy into earth gravitational potential energy
u=mgh
u=12*10^-3*9.8*0.7
=8.23*10^-2
using the Work energy principle
equating the kinetic energy to the potential energy
k +U+w=K2+u2
K+0+0=0+U2
k=8.23*10^-2
force exerted by the grasshopper on the round will be given by tis equation
(F-mg)Ycos
=k
(F-12*10^-3*9.8)*0.004cos 0=8.23*10^-2
F=20.7N
from newtons third law of motion, action and reaction are equal and opposite
F=-20.7N
comparing the forces by the two bodies
F:mg
-20.7:-12*10^-3*9.8
the magnitude of the force applied by the grasshopper is found to be 176 times the gravitational force
The acceleration can be found by:

Where v= velocity and t= time
or
Answer:4.08 N
Explanation:
Given data
superball dropped from a height of 10 cm
Mass of ball
=0.05kg
time of contact
=34.3
s
Now we know impulse =
=Change in momentum
=
and velocity at the bottom is given by
v=
=
=4.081N
Answer:
I believe the answer is weightlifter B
Explanation:
The answer should be:
Angle Of incidence is equal to angle of reflection.