Answer:
False
Explanation: The structure of denatured protein does not change.The primary structure is the same as the secondary or tertiary, hence the non-polar groups are disrupted at high temperatures.
0.11 moles of the gas are present in the sample of dry gas.
Explanation:
Data given:
mass of the gas = 2.1025 grams
volume of the gas = 2.850 litres
temperature = 22 degrees (273.15+22) = 295.15 K
Pressure = 740 mm Hg or 0.973 atm
moles of the gas =?
R = 0.08206 atmL/Mole K
From the ideal gas law the number of moles can be calculated in the sample of dry gas. Number of moles will be determined by the pressure exerted, volume and temperature of the gas.
The formula:
PV = nRT
n = 
putting the values in the above equation:
n = 
= 0.11 moles
0.11 moles of the dry gas is present in the sample given.
Because copper has a higher electrical and thermal conductivity than iron and is not susceptible to oxidation as easily.
Answer:
15.4 g of sucrose
Explanation:
Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m
0.56°C / 1.86 m/°C = m → 0.301 mol/kg
m → molality (moles of solute in 1kg of solvent)
Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg
0.301 mol/kg . 0.150kg = 0.045 moles.
We determine the mass of sucrose, by the molar mass:
0.045 mol . 342 g/1mol = 15.4 g