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suter [353]
2 years ago
10

Q2

Physics
1 answer:
DerKrebs [107]2 years ago
8 0

Answer:

the clock hand of watch which have radium-226 for luminance

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PLEASE HELP
kykrilka [37]

Answer:

Both physical and chemical changes

Explanation:

From the definition of the law of conservation of mass, total mass of all the substances taking part in a chemical reaction is conserved and the number of atoms of each element in the reaction does not change when a new product is formed. Both physical and chemical changes follow the law since when the system is closed to all transfers of matter and energy, the mass of the system must remain constant over time, irrespective of the state.

3 0
2 years ago
Read 2 more answers
What’s the stored energy related to positions of atoms within molecules
zepelin [54]

Cheimcal engery is related to positions of atoms within molecules..

8 0
3 years ago
Develop an algebraic relationship that describes a satellite moving in a circular orbit around a planet if the speed of the sate
lana [24]

Answer:

Explanation:

For this problem we must use Newton's second law where force is gravitational attraction

      F = m a

Since movement is circular, acceleration is centripetal.

      a = v2 / r

Let's replace

      G m M / r² = m v² / r

      G M r = v²

The distance r is from the center of the planet

      r = R + h

      v = √ GM / (R + h)

If the friction force is not negligible

      F - fr = m a

Where the friction force must have some functional relationship, for example

           Fr = b v + c v² +…

Suppose we are high enough for the linear term to derive the force of friction

          G m M / r - (m b v + m c v2) = m v2

          G M / r - b v = v²

We see that the solution of the problem gives lower speeds and that change over time.

To compensate for this friction force, the motors should be intermittently suspended to recover speed.

5 0
3 years ago
What are 2 factors that affect the frictional force between 2 surface science?
Dahasolnce [82]
The weight of the object moving and the roughness of the surfaces
8 0
3 years ago
A vector has the components Ax=−31m and Ay=41m. What is the magnitude of this vector? What angle does this vector make with the
Fudgin [204]

Answer:

Magnitude of vector A is  51.4 m

The angle of vector A with positive x-axis is θ= 127.1^o}

Explanation:

Given is  

A_{x}=-31m

A_{y\\=41m

Let A_{x} and A_{y\\ are components of a vector A,

The magnitude of vector A will be:

A=\sqrt{A_{x}^2 +A_{y}^2}

   =  \sqrt{(-31)^{2} +41^2}

A  = 51.4 m

we know

 θ1= tan^{-1} \frac{A_{y}  }{A_{x} }

   = tan^{-1}(-\frac{41}{31}  )

   =-52.9^{o

Vector A is present in 2nd quadrant as x-component of vector A is negative and y-component is positive.

For finding the angle of vector with positive x-axis,

θ=180-52.9

θ= 127.1^o}

6 0
3 years ago
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