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const2013 [10]
3 years ago
5

Someone help me please i’ll give brainly

Chemistry
2 answers:
belka [17]3 years ago
8 0

Answer:

Gas, liquid, and plasma

Explanation:

Sindrei [870]3 years ago
4 0

Answer:

Liquid, Gas and Plasma

Explanation:

➨Think about it like this if you put a material made out of these and flipped it over which one would have the most effect of change in shape?

▶Liquid molecules slide past each other meaning they are not held in place.

▶Gas molecules are "excited" they bounce around everywhere meaning they are not held in place.

▶Plasma has no fixed shape or volume so it cant be held in place!

▶Solid molecules have a fixed shape so they cannot move on their own.

<u>Hope I helped! Brainliest appreciated!</u>

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It is very expensive to build and maintain a nuclear power plant at first so investors whom want money up front are more reluctant to loan money for one.

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3 years ago
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What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances
belka [17]

The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.

Isotope                    mass amu        Relative abundance

1                                77.9                     14.4

2                               81.9                     14.3

3                               85.9                      71.3

Express your answer to three significant figures and include the appropriate units.

Answer: 84.2 amu

Explanation:

Mass of isotope 1 = 77.9  

% abundance of isotope 1 = 14.4% = \frac{14.4}{100}=0.144

Mass of isotope 2 = 81.9

% abundance of isotope 2 = 14.3% = \frac{14.3}{100}=0.143

Mass of isotope 3 = 85.9

% abundance of isotope 2 = 71.3% = \frac{71.3}{100}=0.713

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(77.9\times 0.144)+(81.9\times 0.143)+(85.9\times 0.713)]

A=84.2amu

Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu

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