To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.
If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,
So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
Answer:
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Explanation:
55
N
Explanation:
Using Newton's second law of motion:
F
=
m
a
Force=mass
×
acceleration
F
=
25
×
2.2
F
=
55
N
So 55 Newtons are needed.
Answer link
Nam D.
Apr 6, 2018
55
N
Explanation:
We use Newton's second law of motion here, which states that,
F
=
m
a
m
is the mass of the object in kilograms
a
is the acceleration of the object in meters per second
F
=
25
kg
⋅
2.2
m/s
2
=
55
N
Divide 2500 g by 500 cc. The quotient is 5 g/cc ... the density.
The radius of the circular path is 1.5 m.
The circumference is then
The ball moves 3π m every 2.2 s, so the speed is
