C) alternating current .
<span>
B)direct current </span>
The strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.
<h3>
</h3><h3>What is the electric field strength?</h3>
The electric field strength is defined as the ratio of electric force to charge.
Given data;
q₁ = 5.4 C
F₁ is the electric force in case1
E is the electric field =?
F₂ is the electric force in case 2
q₂ is the charge 2
The strength of the electric field at that point is;
F₁=Eq₁
E₁=F/q₁
E₁=25.0 N / 5.4 C
E₁=4.587 N/C
The force would this charge experience at that point when the charge is 2.7 C;
F₂=Eq₂
F₂=4.587 N/C × 2.7 C
F₂ = 12.38 N
Hence the strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.
To learn more about the electric field strength, refer to the link;
brainly.com/question/4264413
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Lifting weights, did this yesterday :))
(a) The equivalent resistance of three parallel resistors is (R₁R₂R₃)/(R₁R₂ + R₁R₃ + R₂R₃).
(b) The total circuit current is 12/R.eq.
(c) The voltage drop across and current in each resistor is IR₁, IR₂ and IR₃.
<h3>
Equivalent resistance of three parallel resistors</h3>
The equivalent resistance of three parallel resistors is calculated as follows;
- Let the first resistor = R₁
- Let the second resistor = R₂
- Let the third resistor = R₃
<h3>Total Circuit Current </h3>
The total circuit current is calculated as follows;
V = IR
<h3>Voltage drop in each resistor</h3>
Voltage drop in resistor 1 = IR₁
Voltage drop in resistor 2 = IR₂
Voltage drop in resistor 3 = IR₃
Learn more about parallel circuit here: brainly.com/question/80537
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Answer:
None of the transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.
Explanation:
Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy. If it is in the second energy level, it must have -3.4 eV of energy and so on.
If the electron wants to jump from the first energy level, n = 1, to the second energy level n = 2. The second energy level has higher energy than the first, so to move from n = 1 to n = 2, the electron needs to gain energy. It needs to gain (-3.4) - (-13.6) = 10.2 eV of energy to be excited to the second energy level.
The step from the second energy level to the third is much smaller. It takes only 1.89 eV of energy for this excitation to take place. It takes even less energy to excite electrons in hydrogen from the third energy level to the fourth, and even less from the fourth to the fifth.
None of these transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.
