Answer:
W = N!/(n0! * n1!)
Explanation:
Let n0 = number of particles in the lowest energy state
n1 = number of particles in the excited energy state.
Using this, we can say that N = n0 + n1
From this we can then express the weight, W of the close system by finding the factorials of each particles
W = N!/(n0! * n1!)
Hence, the weight W is expressed as W = N!/(n0! * n1!)
Answer:
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So \frac{\lambda }{2}=20cm
2
λ
=20cm
\lambda =40cmλ=40cm
We have to find the speed of the wave in the string
Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec
So speed of the wave in the string will be 3.2 m/sec
5 m/s
30 divided by 6 is 5
Answer:
Every 2.2 kg is 1 pound. So mulitply 19 * 2.2. It's gonna be equal to 41.8
Explanation:
High energy waves have Gamma rays
