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vova2212 [387]
3 years ago
13

Which is an example of a scientist using a conceptual model to describe a volcano?

Physics
2 answers:
Yuri [45]3 years ago
8 0
I would say D would be the answer. but is this even a real like homework question 

Vedmedyk [2.9K]3 years ago
4 0
D. The scientist uses mud and vinegar (also baking soda) to make a model of the volcano. ~ Science ftw wubba lubba dub dub!
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The beginning development of a star is marked by a supernova explosion, with the gases present in the nebula being forced
GenaCL600 [577]

The beginning development of a star is marked by a supernova explosion, with the gases present in the nebula being forced to scatter. As the star shrinks, radiation of the surface increases and create pressure on the outside shell to push it away and forming a planetary nebula or white dwarf.

4 0
3 years ago
Imagine that you pushed a box, applying a force of 30 Newton’s , over a distance of 5 meters. How much would you do have done ?
kati45 [8]
30 ),which is the force,divided by 5
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7 0
3 years ago
Read 2 more answers
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loris [4]

Answer:

I'm taking a wild guess at c

Explanation:

c. winter solstice

6 0
3 years ago
A 250 g block of ice is removed from the refrigerator at -8.0°C. How much thermal energy does the ice absorb as it warms to room
zlopas [31]

Answer:

Q = 114895 J

Explanation:

To find the thermal energy gained by the ice you use the following formula:

Q=mc(T_2-T_1)+H_f\ m

m: mass of the ice = 0.250kg

T2: final temperature = 22°C

T1: initial temperature = -8.0°C

Hf: heat of fusion of water = 3.34*10^5 J/kg

c: specific heat of water = 4186 J/kg

By replacing the values of the parameters you have:

Q=(0.250kg)(4186J/kg\°C)(22+8)\°C+(3.34*10^5 J/kg)(0.250kg)\\\\Q=114895\ J

where you have considered that ice melts completely

3 0
3 years ago
A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an
Vanyuwa [196]

Answer:

b) 20 kJ

Explanation:

Efficiency of carnot engine = (T₁ - T₂ ) / T₁  Where T₁ is temperature of hot source  and T₂ is temperature of sink .

T₁ = 270 + 273 = 543K

T₂ = 50 + 273 = 323 K

Putting the given values of temperatures

efficiency = (543 - 323) / 543

= .405

heat input = 50 KJ

efficiency = output work / input heat energy

.405 = output work / 50

output work = 20.25 KJ.

= 20 KJ .

6 0
3 years ago
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