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lara31 [8.8K]
3 years ago
6

Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva??

Physics
2 answers:
Brums [2.3K]3 years ago
7 0
<h3>Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva?</h3>

  • Es normal que los quemadores superiores de una estufa eléctrica o una estufa se enciendan y apaguen en configuraciones distintas a Hi. El quemador se encenderá y apagará más de lo normal cuando se utilizan cacerolas que no son planas o que son del tamaño incorrecto para el quemador.

<h2>☆彡Hanna</h2>

#CarryOnLearning

Artyom0805 [142]3 years ago
5 0
<h3>Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva?</h3>

  • Es normal que los quemadores superiores de una estufa eléctrica o una estufa se enciendan y apaguen en configuraciones distintas a Hi. El quemador se encenderá y apagará más de lo normal cuando se utilizan cacerolas que no son planas o que son del tamaño incorrecto para el quemador.

<h2>☆彡Hanna</h2>

#CarryOnLearning

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The nebula hypothesis of the formation of the solar system assumes that the material that became the solar system began as a lar
Zinaida [17]

Answer:

Option (D)

Explanation:

According to the nebula hypothesis that explains the formation of solar system, there occurs changes in terms of its shape as well as the rate of rotation. It is because of the conservation of angular momentum.

The total angular momentum comprising a system remains same or constant, throughout its period of rotation in the absence of net torque. Due to the increasing density, the nebula eventually collapses, and these clouds of gases collides with one another and forms a large cloud. These clouds attains an average velocity and results in an orderly motion, which eventually take the shape of a disk. This is how with time, the sun and the planets have formed, comprising the solar system.

Thus, the correct answer is option (D).

6 0
3 years ago
Two objects with a mass of 10,000-kg each and a distance of 1 meter between them.
Fofino [41]

Answer:

d) What is the force if we doubled both the masses AND we doubled the distance

4 0
3 years ago
A car is traveling at a velocity of 22 m/s when the driver puts on the brakes
Brums [2.3K]

The car’s velocity at the end of this distance is <em>18.17 m/s.</em>

Given the following data:

  • Initial velocity, U = 22 m/s
  • Deceleration, d = 1.4 m/s^2
  • Distance, S = 110 meters

To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

V^2 = U^2 + 2dS

Substituting the values into the formula, we have;

V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}

<em>Final velocity, V = 18.17 m/s</em>

Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>

<em></em>

Read more: brainly.com/question/8898885

8 0
2 years ago
A cyclist traveling at constant speed of 12m/s when he passes a stationary bus.The bus starts moving just as the cyclist passes
Bogdan [553]

Answer:

A.) 8 seconds

B.) 16 seconds

C.) 48 m

Explanation:

Given that a cyclist traveling at constant speed of 12 m/s

and the bus accelerates uniformly at 1.5ms²

A.) The bus has the following parameters

Acceleration a = 1.5 m/s^2

Initial velocity U = 0. Since the bus is starting from rest.

Final velocity V = 12 m/s

Use equation one of linear motion.

V = U + at

Substitute V, U and a into the formula

12 = 0 + 1.5t

1.5t = 12

t = 12/1.5

t = 8 seconds

Therefore, the bus reach the same speed as the cyclist at 8 seconds.

B.) For the cyclist moving at constant speed, acceleration a = 0. Using second equation of motion

h = Ut + 1/2at^2

Since a = 0, the equation is reduced to:

h = Ut.

Also, for the bus,

h = Ut + 1/2at^2

Equate the two equations since the h is the same

Ut = Ut + 1/2at^2

Substitute all the parameters into the formula

12t = 0 + 1/2 × 1.5t^2

12t = 0.75t^2

0.75t = 12

t = 12/0.75

t = 16 seconds

Therefore, the bus takes 16 seconds to catch the cyclist

C.) Use third equation of linear motion.

V^2 = U^2 + 2as

Where s = distance

Substitute V, U and a into the formula

12^2 = 0 + 2 × 1.5 S

144 = 3S

S = 144/3

S = 48 m

8 0
4 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.
Tems11 [23]
Ultraviolet light with a wavelength shorter than visible light and a higher radiant energy than visible light.

The shorter the wavelength, the higher the frequency and energy.
6 0
3 years ago
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