Answer:
With molecular orbitals, we are concerned with the overall distribution (or densities) of electrons between the internuclear axes.
Explanation:
Answer:
Mass = 253.4 g
Explanation:
Given data:
Mass of oxygen required = ?
Mass of hydrogen available = 32.0 g
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass/molar mass
Number of moles = 32.0 g/ 2.02 g/mol
Number of moles = 15.84 mol
Now we will compare the moles of hydrogen and oxygen:
H₂ : O₂
2 : 1
15.84 : 1/2×15.8 = 7.92 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Mass = 7.92 mol × 32.00 g/mol
Mass = 253.4 g
Helium is found in the 1st period of the periodic table. It also is part of the noble gases group in the last column (18th) of the table.
Answer: 5296 L
Explanation:
To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
Putting values in above equation, we get:
Thus volume occupied by oxygen if it were transferred to a container that maintained a pressure of 1.00 atm if the temperature remains constant is 5296 L
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