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Inessa05 [86]
3 years ago
10

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It start

s at the 6-inch mark, crawls to the 19-inch mark, then moves to the 7-inch mark. What was the total distance the ant traveled?
Physics
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

it moves 25 inches.

Explanation:

the east west bit isn't important, ignore it. if an ant starts at 6 then moves to 19 then we need to subtract 19 from 6, that's 13. then it moves to 7. the difference between 19 and 7 is 12. add that to 13 and you get 25. it's important to remember that there is no such thing as negative distance. if it moved, then it counts.

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What are somethings about the Heliocentric model?
Rudik [331]

Answer:

Heliocentrism, a cosmological model in which the Sun is assumed to lie at or near a central point (e.g., of the solar system or of the universe) while the Earth and other bodies revolve around it.

Explanation:

6 0
3 years ago
A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when
Svetllana [295]

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

  • <em>Throat area of the nozzle, </em>A^*<em> = 10 cm² = 0.001 m²</em>
  • <em>The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²</em>
  • <em>Air pressure at sea level = 101.325 kPa</em>

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896

From supersonic isentropic table, at \frac{A}{A^*} = 2.896, we can determine the following;

M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954

The tank pressure is calculated as follows;

\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

Learn  more about converging-diverging nozzle design here: brainly.com/question/13889483

8 0
2 years ago
Jimmy walks 3 miles east then 1 mile west. What is the distance Jimmy traveled?
AleksAgata [21]

Answer:

2 miles

Explanation:

Jimmy walked forward 3 miles east (to the right)

Then, he backtracked and walked 1 mile west (to the left)

This can be written as:

3 - 1 = ?

3 - 1 = 2

Therefore, Jimmy traveled a total of 2 miles.

4 0
3 years ago
Two blocks on a frictionless horizontal surface are on a collision course. one block with mass 0.6 kg moves at 0.8 m/s to the ri
Elanso [62]

First we can say that since there is no external force on this system so momentum is always conserved.

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.6*0.8 + 1.2*0 = 0.6*v_{1f} + 1.2*v_{2f}

0.48= 0.6*v_{1f} + 1.2*v_{2f}

0.8  = v_{1f} + 2v_{2f}

now by the condition of elastic collision

v_{2f} - v_{1f} = 0.8 - 0[\tex]now add two equations[tex]3*v_{2f} = 1.6

v_{2f} = 0.533 m/s

also from above equation we have

v_{1f} = -0.267 m/s

So ball of mass 0.6 kg will rebound back with speed 0.267 m/s and ball of mass 1.2 kg will go forwards with speed 0.533 m/s.

8 0
4 years ago
Which has a charge with the greatest magnitude?
pishuonlain [190]

Answer:

an object with charge -3

3 0
3 years ago
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