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3 years ago

What does Mature Male mean?

Physics

1 answer:

Debora [2.8K]3 years ago

7 0

Answer:

mature man means giving up the need to conquer and vanquish and being okay with letting others get their way.

Explanation:

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An apparatus like the one Cavendish used to ﬁnd G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg.

Ber [7]

Answer:

The magnitude of gravitational force between two masses is $4.91\times 10^{-9}\ N$ .

Explanation:

Given that,

Mass of first lead ball, $m_1=5.2\ kg$

Mass of the other lead ball, $m_2=0.046\ kg$

The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m

We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

$F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67259\times 10^{-11}\times \dfrac{5.2\times 0.046}{(0.057)^2}\\\\F=4.91\times 10^{-9}\ N$

So, the magnitude of gravitational force between two masses is $4.91\times 10^{-9}\ N$ . Hence, this is the required solution.

5 0

3 years ago

Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f

Sergeu [11.5K]

Answer:

f = 55mm, h ’= -9.89 cm

f = 200 mm, h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

$\frac{1}{q} = \frac{1}{f} - \frac{1}{p}$

$\frac{1}{q_1}$ = $\frac{1}{0.55} - \frac{1}{10}$

$\frac{1}{q_1}$ = 1.718

q₁ = 0.582 m

lens with f₂ = 200mm = 2m

$\frac{1}{q_2}$ = $\frac{1}{2} - \frac{1}{10}$

$\frac{1}{q_2}$ = 0.4

q₂ = 2.5 m

the magnification of a lens is given by

m = $\frac{h'}{h} = - \frac{q}{p}$

h ’= $- \frac{q}{p} \ h$

let's calculate for each lens

f = 55mm

h '= - 0.582 / 10 1.7

h ’= 0.0989 m

h ’= -9.89 cm

f = 200 mm

h '= - 2.5 / 10 1.7

h ’= -0.425 m

h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0

3 years ago

What is the resultant of the two vectors shown?

lianna [129]

Explanation:

The correct is (c). cuz, the tail of A and the tip of B will join

3 0

2 years ago

Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings

Hatshy [7]

Answer:0.316 rad/s

Explanation:

Given

mass of Person $m=65 kg$

velocity of person $v=3.8 m/s$

diameter of turntable $d=6.5 m$

moment of Inertia of the table $I_0=1850 kg-m^2$

Moment of inertia of Person I

$I=mr^2=65\times (\frac{6.5}{2})^2$

$I=686.56 kg-m^2$

initial angular velocity $\omega _1=\frac{v}{r}$

$\omega _1=\frac{3.8}{3.25}=1.17 rad/s$

Conserving Angular momentum

$I\omega _1=(I+I_0)\omega _2$ , where $\omega _2=final\ angular\ velocity$

$686.56\times 1.17=(686.56+1850)\times \omega _2$

$\omega _2=\frac{686.56}{2536.56}\times 1.17$

$\omega _2=0.316 rad/s$

4 0

3 years ago

Car A of mass 1200kg traveling at 10m/s , collided in too the back of the car B, which is stationary. Following the collision,.

Nina [5.8K]

Answer:

Car B has a mass of 800 kg.

General Formulas and Concepts:

Momentum

Law of Conservation of Momentum: $\displaystyle m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_{f}$

Explanation:

Step 1: Define

Identify variables

[Given] m₁ = 1200 kg

[Given] v₁i = 10 m/s

[Solve] m₂

[Given] v₂i = 0 m/s

[Given] vf = 6 m/s

Step 2: Solve for m₂

Substitute in variables [Law of Conservation of Momentum]: (1200 kg)(10 m/s) + m₂(0 m/s) = (1200 kg + m₂)(6 m/s)
Multiply: 12000 kg · m/s = (1200 kg + m₂)(6 m/s)
Isolate m₂ term: 2000 kg = 1200 kg + m₂
Isolate m₂: 800 kg = m₂

4 0

3 years ago

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