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prohojiy [21]
3 years ago
10

When applying monomer liquid and polymer powder nail enhancements, after dipping the brush in monomer liquid and removing the ex

cess, you should:
Chemistry
1 answer:
kvv77 [185]3 years ago
6 0

Answer: Dip the same brush into the polymer powder and slightly rotate it

Explanation:

After removing the excess, dipping the same brush into the polymer powder and rotating it slightly would form a paste solution that can be used for enhancement, e.g nail enhancement called sculptured nails.

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Na2o + h2so4 ———&gt; na2so4 + h2o<br><br><br> Can anyone balance this please!!??
marysya [2.9K]

Answer:

The equation is already balanced. There's an equal number of materials on each side of the equation.

4 0
3 years ago
Water’s unique properties, high heat capacity, high density, solid phase less dense than liquid phase can be attributed to
Xelga [282]

Answer:

B- The polarity of the molecules and hydrogen bonding between molecules.

Explanation:

Hope this helps:)

4 0
2 years ago
Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

6 0
2 years ago
A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molar concentration of the solution.
blsea [12.9K]
The molarity is moles/liters.

First, convert 4,000 mL to L:

4000 mL --> 4 L

Now, you must convert the 17 g of solute to moles by dividing the number of grams by the molar mass. The molar mass of AgNO3 is <span>169.87 g/mol:

17 / 169.87 = .1

Now that you have both the number of moles and the liters, plug them into the initial equation of moles/liters:

.1/4 = .025</span>
3 0
2 years ago
Read 2 more answers
Which of the following items is a salt? (1 point)
Tems11 [23]

  • Calcium carbonate is the  salt  among the given options.

  • Calcium carbonate ( CaCO3) can be regarded as  which appears as white and odorless powder or  as a colorless crystals it is  insoluble in water.

  • The chemical  formula is CaCO3. It can be used as an antacid as well as food colouring and a  food firming agent and a fertilizer.

  • Calcium carbonate is calcium salt as well as carbonate salt with one-carbon compound

  • Salt can be regarded as substance which is  produced by reaction between acid and  base. It  consists negative ion (anion) of that acid as well as positive ion (cation) of the base.

  • Sodium hydroxide is a base and not a salt

  • Carbonic acid is an acid and not a salt

  • Therefore, calcium carbonate is the only salt in the among the given options.

Learn more at ; brainly.com/question/14091731?referrer=searchResults

5 0
2 years ago
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