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3 years ago

1. Why does this traditional folk dance called 'tinikling?

Physics

1 answer:

mestny [16]3 years ago

7 0

Answer:

The Tinikling is said to be named after the long-legged bird called the tinikling in the Philippines. Someone who dances the Tinikling imitates the movements of a tinikling bird (hence, tinikling-like) as the bird walks over the grass or dodges bamboo traps set by Filipino farmers on vast rice fields.

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Magnitude F have a

lakkis [162]

Answer:

120°

Explanation:

Given forces with magnitude F and F

Applying the parallelogram law of vector

Where resultant is given as :

R = √(A^2 + B^2 + 2ABCos Ф

WHERE A and B are two forces with angle Ф

F =√(F^2 + F^2 + 2F * F Cos Ф

Square both sides

F^2 = F^2 + F^2 + 2F^2 CosФ

F^2 - 2F^2 = 2F^2 CosФ

- F^2 = 2F^2 Cos Ф

Divide both sides by 2F^2

- 1 / 2 = CosФ

Cosine(theta) = - 1/2

Ф = cosi^-1 (-1/2)

Ф = 120°

4 0

4 years ago

A coil is wrapped with 300 turns of wire on the perimeter of a circular frame (radius = 8.0 cm). Each turn has the same area, eq

MAVERICK [17]

Answer:

Approximately 18 volts when the magnetic field strength increases from $\rm 20\; mT$ to $\rm 80\;mT$ at a constant rate.

Explanation:

By the Faraday's Law of Induction, the EMF $\epsilon$ that a changing magnetic flux induces in a coil is:

$\displaystyle \epsilon = N \cdot \frac{d\phi}{dt}$ ,

where

$N$ is the number of turns in the coil, and
$\displaystyle \frac{d\phi}{dt}$ is the rate of change in magnetic flux through this coil.

However, for a coil the magnetic flux $\phi$ is equal to

$\phi = B \cdot A\cdot \cos{\theta}$ ,

where

$B$ is the magnetic field strength at the coil, and
$A\cdot \cos{\theta}$ is the area of the coil perpendicular to the magnetic field.

For this coil, the magnetic field is perpendicular to coil, so $\theta = 0$ and $A\cdot \cos{\theta} = A$ . The area of this circular coil is equal to $\pi\cdot r^{2} = \pi\times 8.0\times 10^{-2}\approx \rm 0.0201062\; m^{2}$ .

$A\cdot \cos{\theta} = A$ doesn't change, so the rate of change in the magnetic flux $\phi$ through the coil depends only on the rate of change in the magnetic field strength $B$ . The size of the magnetic field at the instant that $B = \rm 50\; mT$ will not matter as long as the rate of change in $B$ is constant.

$\displaystyle \begin{aligned} \frac{d\phi}{dt} &= \frac{\Delta B}{\Delta t}\times A \\&= \rm \frac{80\times 10^{-3}\; T- 20\times 10^{-3}\; T}{20\times 10^{-3}\; s}\times 0.0201062\;m^{2}\\&= \rm 0.0603186\; T\cdot m^{2}\cdot s^{-1}\end{aligned}$ .

As a result,

$\displaystyle \epsilon = N \cdot \frac{d\phi}{dt} = \rm 300 \times 0.0603186\; T\cdot m^{2}\cdot s^{-1} \approx 18\; V$ .

9 0

4 years ago

Which conclusion can be made based on the information in the table?

Sergeeva-Olga [200]

Answer:

The correct option is (b).

Explanation:

The relation between the wavelength and frequency is given by :

$\lambda=\dfrac{v}{f}$

Where

v is the wave speed

f is the frequency of a wave

It is clear from the above equation that the wavelengths and frequency can vary inversely to produce the same wave speed.

6 0

3 years ago

A 15.5 kg block is pulled by two forces. The first is 11.8N at a 53.7 angle and the second is 22.9 N at a -15.8 angle. What is t

anygoal [31]

Answer:

α = 6.43° (Angle respect to the horizontal axis-x)

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces must be equal to the product of mass by acceleration.

Since we have two forces and we know their magnitudes and their directions, we can sum these into their X & y components, in this way we can find the resulting force and apply it in Newton's second law.

F1x = 11.8*cos(53.7) = 6.98 [N]

F1y = 11.8*sin(53.7) = 9.5 [N]

Now with the second force:

F2x = 22.9*cos (15.8) = 22.03 [N]

F2y = - 22.9*sin (15.8) = - 6.23 [N]

Now we sum the forces in the x and y axes:

Fx = F1x + F2x = 6.98 + 22.03 = 29.01 [N]

Fy = F1y + F2y = 9.5 - 6.23 = 3.27 [N]

Now using the Pythagorean theorem we can find the resulting force.

F = √(Fx² + Fy²)

F = √ (29.01)² + (3.27)²

F = 29.19 [N]

Using Newton's second law, we have:

F = m*a

where:

F = force = 29.19 [N]

m = mass = 15.5 [kg]

a = acceleration [m/s²]

a = 29.19/15.5

a = 1.88 [m/s²]

The direction of the acceleration is the same direction of the force, therefore we need to find the angle.

tan(α) = Fy/Fx

tan(α) = 3.27/29.01

α = tan⁻¹(0.1127)

α = 6.43° (Angle respect to the horizontal axis-x)

3 0

3 years ago

What factors determine the magnitude of the electric force between two particles ?

sattari [20]

Answer:

Force between two particles depends on the magnitude of charge on the particles and distance between them

Explanation:

We know that

According to coulomb's law electric force between two Particles is given by

$F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2}=\frac{KQ_1Q_2}{R^2}$ , here K is constant $Q_1\ and\ Q_2\ charge\ on\ the\ particles$

R is the distance between the charge particles

So force between two particles depends on the magnitude of charge on the particles and distance between them

6 0

3 years ago

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1. Why does this traditional folk dance called 'tinikling?​

1. Why does this traditional folk dance called 'tinikling?