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oee [108]
3 years ago
11

6. Rock Ais thrown horizontally off a cliff with a velocity of 15 m/s. The rock lands 75m from

Physics
1 answer:
Harman [31]3 years ago
3 0

Answer:

5  seconds

Explanation:

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Identify the energy transformation is image below
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Answer:

chemical to mechanical

hope it helps have a nice day

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If you were to mix 3 liters of 20 degrees celsius water with 4 liters of 30 degrees water at 7 liters of water what temperature
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Lets say final temperature is @ celsius
3c(@-20)= 4c([email protected])
[email protected]=180
@=180/7
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Why can television satellites, which broadcast information as electromagnetic radiation, send signals from the vacuum of space?
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The answer is b. Electromagnetic waves do not need a medium to travel through.
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A child on a playground swing makes a complete to-and-fro swing each two seconds. The frequency of the swing is
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Frequency=f
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4 0
3 years ago
Tungsten has a temperature coefficient of resistivity of 0.0045 (c°)-1. a tungsten wire is connected to a source of constant vol
Murljashka [212]

Answer:

131.1^{\circ}C

Explanation:

The power delivered in the wire is given by:

P=\frac{V^2}{R}

where V is the voltage of the battery and R is the resistance of the wire.

Since the voltage of the battery is constant, we can rewrite this equation as follows:

V^2 = PR=const. (1)

At the beginning, the initial resistance is R_0, and the power delivered is P_0. Later, when the temperature increases, the power becomes P_1 = \frac{2}{3}P_0, and the new resistance is R_1. Using (1), we can write

P_0 R_0 = \frac{2}{3}P_0 R_1\\R_1 = \frac{3}{2}\frac{P_0 R_0}{P_0}=\frac{3}{2}R_0 (2)

So, the new resistance must be 3/2 of the initial resistance.

We know that the resistance increases linearly with the temperature, as

R_1 = R_0 (1+\alpha \Delta T)

where

\alpha = 0.0045 ^{\circ}C^{-1} is the temperature coefficient

\Delta T is the change in temperature

Using (2), we can rewrite this equation as

\frac{3}{2}R_0 = R_0(1+ \alpha \Delta T)

and we find:

\frac{3}{2}=1+\alpha \Delta T\\\Delta T=\frac{\frac{3}{2}-1}{\alpha}=111.1 ^{\circ}

So, the new temperature of the wire must be

T_f = 21^{\circ}+111.1^{\circ}=132.1^{\circ}

6 0
3 years ago
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