-9.8 m/s^2 would be right.
The distance of the straight wire carrying a current of 15 A is 2.72 mm
<h3 /><h3>What is distance?</h3>
Distance is the length between two points.
To calculate the distance, the straight wire carrying a current of 15 A, we use the formula below.
⇒ Formula:
- r = μ₀i/2πB................. Equation 1
⇒ Where:
- B = Magnetic field
- i = Current
- r = Distance from the straight wire and the magnetic field
- π = pie
- μ₀ = Permeability of free space
From the question,
⇒ Given:
- I = 15 A
- B = 1.1 mT = 1.1×10⁻³ T
- μ₀ = 4π×10⁻⁷ H/m
Substitute these values into equation 1
- r = (4π×10⁻⁷×15)/(2π×1.1×10⁻³)
- r = 2.72×10⁻³ m
- r = 2.72 mm
Hence, the distance of the straight wire carrying a current of 15 A is 2.72 mm
Learn more about distance here: brainly.com/question/2854969
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C i’m pretty sure cuz the rest of them happen after
Answer:
a) , b)
Explanation:
a) The final angular speed is:
The angular acceleration experimented by the centrifuge is determined by means of the following kinematic expression:
b) The change in angular position is:
Lastly, the total amount of revolutions made by the centrifuge is: