Question

If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it? (Hint: Use MsVs = MdVd to find the amount of concentrated solution you need, then add water to reach 100 mL.) Show your work.

Answer 1

Answer:

We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to  make 100 mL of a 0.2 M fruit drink solution.

Explanation:

• Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

(MV) before dilution = (MV) after dilution.

M before dilution = 1.0 M, V before dilution = ??? mL.

M after dilution = 0.2 M, V after dilution = 100 mL.

∴ V before dilution = (MV) after dilution / M before dilution = (0.2 M)(100 mL) / (1.0 M) = 20.0 mL.

So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to  make 100 mL of a 0.2 M fruit drink solution.

Answer 2

Answer:

The volume of the 1.0 M juice solution is 20 mL.

Explanation:

Concentration of juice = $M_1=1.0m$

Volume of the juice = $V_1$

Concentration of Juice we need = 0.2

Volume of the 0.2 M juice we need $V_2= 100 mL=0.1L$

Using dilution formula :

$M_1V_1=M_2V_2$

$1.0M \times V_1=0.2 M\times 0.1 L$

$V_1=0.02 L = 20 mL$

We have to add 80 mL of water to 20 ml of solution which has concentration of juice equal to 1.0 M.