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trapecia [35]
3 years ago
12

A a healthy diet and exercise have an impact on the overall health of

Physics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

This would be answer choice A

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The number 3 in hydrogen in NH33 is the
frosja888 [35]

Answer:

no of atoms

Explanation:

for each amonia molecule one nitrogen atom bind with 3 hydrogen atoms

4 0
4 years ago
Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0
3 years ago
You drop a rock off a bridge. The rock's height, h (in feet above the water), after t seconds is modeled by h = – 16 t2 + 541. W
marin [14]
<span>h ( t) = h(1 sec) = -16t^2 + 541

so h (2 sec) = -16*(2)^2 + 541 = -64 + 541 = <span>477 ft

Therefore, </span></span>the height of the rock after 2 seconds is 477 feet.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
5 0
4 years ago
How long will it take a basketball starting from rest to roll without slipping 2.6 m down an incline that makes an angle of 30.8
Romashka-Z-Leto [24]

Answer:

<em>t = 1.02 s</em>

Explanation:

friction = 0 N (no slipping)

downward force along the inclined plane = F = mgsin(30.8)

                                                                        F = ma

⇒                                                                      a = 9.81 sin(30.8)

                                                                         a = 5.02 m/s^2

now we have

displacement = s = 2.6 m

acceleration   = a = 5.02m/s^2

initial velocity = Vi = 0m/s

time                 = t =  ?

<u>APPLYING THE 2ND EQUATION OF MOTION:</u>

<em>    S = (Vi)(t)+0.5at^2</em>

<em>2.6 = 0(t) + 0.5 * 5.02 * t^2</em>

<em>t = 1.02 s</em>

7 0
3 years ago
Consider n equal positively charged particles each of magnitude Q/n placed symmetrically around a circle of radius a. Calculate
Sonja [21]

Answer: Magnitude of electric field =p × Ke × Q/d^3

Explanation: Using Coulombs law of point charge,each charge on the circle would exert a fieldEc at point given by:

Ec= Ke × (Q/n)/d^2

Where Ke= Coulomb's constant

d= distance between the charges and the point of measurement, P with d^2=a^2+p^2

(Q/n)= Magnitude of the charge.

For charges in a circle,all the force components and direction(x,z) are cancelled by the symmetry,leaving only the vertical force(y-direction)

The Resultant vector will be

Ecy=Eq × sin(theta)

Ecy=Ke × (Q/n)/d^2 ×(p/d)

Adding the forces from all the charges,the magnitude of electric field Ey=n×Ecy

/Ey/= n ×[Ke ×(Q/n)/d^2 ×(p/d)]

/Ey/= p × Ke × (Q/d^3)

3 0
3 years ago
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